car*_*oig 3 xml t-sql sql-server openxml
我有一个xml文档,我想用它来更新存储过程中的值.我可以使用OPENXML处理XML,但我对提取我想要的值感到困惑.xml中的每一行都是产品记录,我想为每个属性创建一个变量.Cell0是ID,Cell2描述等
DECLARE @idoc int
DECLARE @doc varchar(1000)
SET @doc ='
<products>
<rows>
<row>
<cell>1</cell>
<cell>BALSAMO DERMOSCENT</cell>
<cell>1.00</cell>
<cell>0.00</cell>
<cell>18.00</cell>
<cell>18.00</cell>
<cell>8.00</cell>
<cell>427</cell>
<cell>No</cell>
</row>
<row>
<cell>2</cell>
<cell>BAYTRIL 150 MG 1 CPDO</cell>
<cell>1.00</cell>
<cell>0.00</cell>
<cell>3.50</cell>
<cell>3.50</cell>
<cell>8.00</cell>
<cell>57</cell>
<cell>No</cell>
</row>
</rows>
</products>'
--Create an internal representation of the XML document.
EXEC sp_xml_preparedocument @idoc OUTPUT, @doc
-- Execute a SELECT statement that uses the OPENXML rowset provider.
SELECT *
FROM OPENXML (@idoc, '/products/rows/row/cell',1)
with (Col1 varchar(29) 'text()')
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运行上面的查询会返回xml中每个CELL的1条记录.我希望能够为每个单元返回1条记录,每个单元格具有不同的列,例如: -
Prod Description Qty
---------- -------------------- --------
1 BALSAMO DERMOSCENT 1.00
2 BAYTRIL 150 MG 1 CPDO 1.00
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我正在使用MSSQL 2008
我想出了以下哪些能为我完成工作
DECLARE @idoc int
DECLARE @doc varchar(1000)
SET @doc ='
<products>
<rows>
<row>
<cell>1</cell>
<cell>BALSAMO DERMOSCENT</cell>
<cell>1.00</cell>
<cell>0.00</cell>
<cell>18.00</cell>
<cell>18.00</cell>
<cell>8.00</cell>
<cell>427</cell>
<cell>No</cell>
</row>
<row>
<cell>2</cell>
<cell>BAYTRIL 150 MG 1 CPDO</cell>
<cell>1.00</cell>
<cell>0.00</cell>
<cell>3.50</cell>
<cell>3.50</cell>
<cell>8.00</cell>
<cell>57</cell>
<cell>No</cell>
</row>
</rows>
</products>'
--Create an internal representation of the XML document.
EXEC sp_xml_preparedocument @idoc OUTPUT, @doc
-- Execute a SELECT statement that uses the OPENXML rowset provider.
SELECT *
FROM OPENXML (@idoc, '/products/rows/row',1)
with (pLineNo int 'cell[1]/text()',
pDesc varchar(50) 'cell[2]/text()',
pQty float 'cell[3]/text()',
pCost float 'cell[4]/text()',
pPvp float 'cell[5]/text()',
pTotal float 'cell[6]/text()',
pIva float 'cell[7]/text()',
pId int 'cell[8]/text()',
pnoFact varchar(5) 'cell[9]/text()')
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