我想为选定架构中的选定表获得所需的结果,像这样
column_name | data_type | description
-----------------------------------------
id | integer | id of bill
name | character |
address | character | adress of buyer
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请注意,有些列没有描述(列注释)。
现在,我只得到了这个查询,它给我很好的结果,但只得到了带有注释的列(对于所选表中没有注释的列,则不会在输出中显示)。
我的查询仅返回具有注释的列的数据
SELECT c.column_name, c.data_type, pgd.description
from pg_catalog.pg_statio_all_tables as st
inner join pg_catalog.pg_description pgd on (pgd.objoid=st.relid)
inner join information_schema.columns c on (pgd.objsubid=c.ordinal_position and c.table_schema=st.schemaname and c.table_name=st.relname)
where table_schema = 'public' and table_name = 'some_table';
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如何获取没有评论的列?
有功能 col_description(table_oid, column_number)
select column_name, data_type, col_description('public.my_table'::regclass, ordinal_position)
from information_schema.columns
where table_schema = 'public' and table_name = 'my_table';
column_name | data_type | col_description
-------------+-----------+-------------------
gid | integer | a comment for gid
id | integer |
max_height | numeric |
(3 rows)
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因为information_schema.columns该表肯定包含数据,并且您不是第一个引用它,right outer join所以您需要:
t=# SELECT c.column_name, c.data_type, pgd.description
from pg_catalog.pg_statio_all_tables as st
inner join pg_catalog.pg_description pgd on (pgd.objoid=st.relid)
right outer join information_schema.columns c on (pgd.objsubid=c.ordinal_position and c.table_schema=st.schemaname and c.table_name=st.relname)
where table_schema = 'public' and table_name = 's150';
column_name | data_type | description
---------------+-----------+-------------
customer_name | text |
order_id | text |
order_date | date |
(3 rows)
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