我试图对象转换为JSON在我的updateDetails方法,但我得到undefined的console.log转换为后json。
这是怎么了?我的鳕鱼是..
HTML:
<body ng-app="myApp" ng-controller="myCtrl" ng-init="init()">
<form id="show_details" ng-repeat="data in editProjDetails">
<div>
<label><input type="text" class="form-control projectName required onlyAlphaNumeric" ng-model="data.ProjectName" ng-disabled="all"></label>
</div>
<div>
<label><input type="text" class="form-control client required onlyAlphabets" ng-model="data.Client" ng-disabled="all"></label>
</div>
<div id="projectCoOrdBlock">
<label><input type="text" class="form-control projectCoOrd onlyAlphabets" ng-model="data.ProjectCoordinator" ng-disabled="true"></label>
</div>
<div>
<label><input type="text" class="form-control required onsiteCoOrd onlyAlphabets" ng-model="data.OnsiteCoordinator" ng-disabled="all"></label>
</div>
<div id="resourceBlock">
<label><input type="text" class="form-control resource onlyNumeric" ng-model="data.ResourceAllocated" ng-disabled="true"></label>
</div>
<div>
<span class="pull-right btnMarginTop">
<button class="btn btn-primary" id="projectDetailsEdit" ng-if="!editMode" ng-click="editDetails()">Edit</button>
<button class="btn btn-primary" id="projectDetailsUpdate" ng-if="editMode" ng-click="updateDetails(data)">Update</button>
</span>
</div>
</form>
</body>
Run Code Online (Sandbox Code Playgroud)
脚本
var app = angular
.module("myApp", [])
.controller("myCtrl", function ($scope, $http) {
$scope.editMode = false;
$scope.all = true;
$scope.init = function () {
$scope.getId();
}
$scope.getId = function () {
var url = document.URL;
var id = /id=([^&]+)/.exec(url)[1];
var result = id ? id : ' ';
$scope.getProjectDetails(result);
}
$scope.goEvent = function () {
$scope.editMode = !$scope.editMode;
}
$scope.updateDetails = function (data) {
debugger
$scope.editedArrayDetails = [];
$scope.editedArrayDetails.push(data);
$scope.json = angular.toJson($scope.data);
console.log($scope.data)
$scope.goEvent();
}
})
Run Code Online (Sandbox Code Playgroud)
这是我的json fromat:
我想用这些名称保存数据
if ($scope.json) {
$scope.json = { "project_id": Id, "name": ProjectName, "client": Client, "onsite_coordinator": OnsiteCoordinator };
}
Run Code Online (Sandbox Code Playgroud)
但我得到Id,ProjectName,Client,OnsiteCoordinator是不确定的。
您将作为参数传递data,因此不应使用$scope前缀。相反,只使用数据。
$scope.updateDetails = function (data) {
$scope.editedArrayDetails = [];
$scope.editedArrayDetails.push(data);
$scope.json = angular.toJson(data);
console.log($scope.json )
$scope.goEvent();
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
16952 次 |
| 最近记录: |