"bills": [
{
"refNo": 17,
"billDate": "1-apr-2016",
"dueDate": "30-apr-2016",
"pendingAmount": 4500,
"overdueDays": 28
},
{
"refNo": 20,
"billDate": "15-apr-2016",
"dueDate": "3-may-2016",
"pendingAmount": 56550,
"overdueDays": 15
}
]
Run Code Online (Sandbox Code Playgroud)
我想对“pendingAmount”字段求和。它应该像pendingAmount一样返回:61050
您可以使用Array#map然后Array#reduce将对象展平,然后对地图的结果求和:
bills.map(bill => bill.pendingAmount).reduce((acc, bill) => bill + acc);
Run Code Online (Sandbox Code Playgroud)
这是一个片段:
bills.map(bill => bill.pendingAmount).reduce((acc, bill) => bill + acc);
Run Code Online (Sandbox Code Playgroud)
希望能帮助到你,
此致,
小智 5
reduce() 方法对累加器和数组中的每个元素(从左到右)应用一个函数以将其减少为单个值。
var bills = [
{
"refNo": 17,
"billDate": "1-apr-2016",
"dueDate": "30-apr-2016",
"pendingAmount": 4500,
"overdueDays": 28
},
{
"refNo": 20,
"billDate": "15-apr-2016",
"dueDate": "3-may-2016",
"pendingAmount": 56550,
"overdueDays": 15
}
];
var result = bills.reduce(function(_this, val) {
return _this + val.pendingAmount
}, 0);
console.log(result)
//61050 answerRun Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
10428 次 |
| 最近记录: |