动态更改json属性名称并序列化

Question

我想动态更改 json 属性名称并序列化对象。

这是我的两个不同实体的 json

对于客户

{
  "userName": "66666",
  "password": "test1234",  
  "customersList": [
    {
      "address": "Test Stree2",
      "customerNumber": "US01-000281",
      "city": ""

    }
  ]
}

联系方式

{
  "userName": "66666",
  "password": "test1234",  
  "contactList": [
    {
      "address": "Test stree1",
      "contactNumber": "US01-000281",
      "city": ""

    }
  ]
}

保存该数据的模型如下

public class URequest<T>
    {

        [JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
        public string userName { get; set; }

        [JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
        public string password { get; set; }    

       [JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
        public IList<T> requestList { get; set; }

    }

上面的代码中可能包含或 的requestList列表，但在发送时我想将json 属性名称更改为相应的实体名称，即因为它将是并且因为它将在序列化后。contactscustomerrequestListcustomercustomerListcontactcontactList

Answer 1

您可以创建自定义 JsonConverter。

使用自定义 JsonConverter 来更改对象部分的序列化

例子

public class Customer
{
    public string Name { get; set; }
}

public class Client
{
    public string Name { get; set; }
}

public class URequest<T>
{

    [JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
    public string userName { get; set; }

    [JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
    public string password { get; set; }

    [JsonIgnore]
    public IList<T> requestList { get; set; }

}

public class URequestConverter<T> : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return (objectType == typeof(URequest<T>));
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        var objectType = value.GetType().GetGenericArguments()[0];
        URequest<T> typedValue = (URequest<T>) value;

        JObject containerObj = JObject.FromObject(value);

        containerObj.Add($"{objectType.Name.ToLower()}List", JToken.FromObject(typedValue.requestList));
        containerObj.WriteTo(writer);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}

你可以这样使用它

    [TestMethod]
    public void TestMethod1()
    {
        URequest<Customer> request = new URequest<Customer>();
        request.password = "test";
        request.userName = "user";
        request.requestList = new List<Customer>();

        request.requestList.Add(new Customer() { Name = "customer" });

        JsonSerializerSettings settings = new JsonSerializerSettings();
        settings.Formatting = Formatting.Indented;
        settings.Converters.Add(new URequestConverter<Customer>());

        Console.WriteLine(JsonConvert.SerializeObject(request, settings));
    }