如何更改 Plotly 3D 散点图中的颜色

Question

我正在学习如何使用他们的示例和我自己的数据在 Plotly 上绘制 3D 散点图。样品在这里

我可以绘制散点图（它看起来很酷），但我无法让不同的数据系列点显示为单独的颜色。

import plotly #load plotly for plotting
import plotly.plotly as py
from plotly import tools
from plotly.graph_objs import * #all the types of plots that we will plot here
plotly.offline.init_notebook_mode() # run at the start of every ipython notebook

trace1 = Scatter3d(
    x = res,
    y = lc,
    z = spent,
    mode='markers',
    marker=dict(
        size=12,
        color=["z","y","x"],  # set color to an array/list of desired values
        colorscale='Viridis',   # choose a colorscale
        opacity=0.8
    )
)


data = [trace1]
layout = Layout(
    margin=dict(
        l=0,
        r=0,
        b=0,
        t=0
    )
)
fig = Figure(data=data, layout=layout)
plotly.offline.iplot(fig, filename='3d-scatter-colorscale')

我尝试过使用其他单独来源的示例，例如 Cambridge Spark，但我只是没有经验来弄清楚如何使其工作。

我确信这是一些简单的事情，我错过了但看不到它。

Answer 1

我应该以我的系列之一作为标记点。在本例中，我使用花费而不是 x、y、z 列表

import plotly #load plotly for plotting
import plotly.plotly as py
from plotly import tools
from plotly.graph_objs import * #all the types of plots that we will plot here
plotly.offline.init_notebook_mode() # run at the start of every ipython notebook

trace1 = Scatter3d(
    x = res,
    y = lc,
    z = spent,
    mode='markers',
    marker=dict(
        size=12,
        color=spent,  # set color to an array/list of desired values
        colorscale='Viridis',   # choose a colorscale
        opacity=0.8
    )
)


data = [trace1]
layout = Layout(
    margin=dict(
        l=0,
        r=0,
        b=0,
        t=0
    )
)
fig = Figure(data=data, layout=layout)
plotly.offline.iplot(fig, filename='3d-scatter-colorscale')