Moe*_*oeb 3 sql database oracle date-arithmetic
SQL> select to_timestamp('2010-12-14:09:56:53') - to_timestamp('2010-12-14:09:56:46') from dua
l;
select to_timestamp('2010-12-14:09:56:53') - to_timestamp('2010-12-14:09:56:46') from dual
*
ERROR at line 1:
ORA-01843: not a valid month
SQL> select to_date('2010-12-14:09:56:53') - to_date('2010-12-14:09:56:46') from dual;
select to_date('2010-12-14:09:56:53') - to_date('2010-12-14:09:56:46') from dual
*
ERROR at line 1:
ORA-01861: literal does not match format string
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做正确的方法是什么?
2010-12-14:09:56:53
minus
2010-12-14:09:56:46
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在Oracle SQL中?
vls*_*vls 12
您必须指定时间戳字符串所在的格式TO_DATE和TO_TIMESTAMP函数:
select
to_date('2010-12-14:09:56:53', 'YYYY-MM-DD:HH24:MI:SS') -
to_date('2010-12-14:09:56:46', 'YYYY-MM-DD:HH24:MI:SS')
from dual;
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结果将以天为单位,您可以乘以86,400得到秒:
TO_DATE('2010-12-14:09:56:53','YYYY-MM-DD:HH24:MI:SS')-TO_DATE('2010-12-14:09:56
--------------------------------------------------------------------------------
.000081019
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使用TO_TIMESTAMP:
select
to_timestamp('2010-12-14:09:56:53', 'YYYY-MM-DD:HH24:MI:SS') -
to_timestamp('2010-12-14:09:56:46', 'YYYY-MM-DD:HH24:MI:SS')
from dual;
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结果将采用以下TIMESTAMP格式:
TO_TIMESTAMP('2010-12-14:09:56:53','YYYY-MM-DD:HH24:MI:SS')-TO_TIMESTAMP('2
---------------------------------------------------------------------------
+000000000 00:00:07.000000000
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