man*_*ixx 5 bash shell json jq
我有给定的JSON和想改变id所有元素的值,这与开始test的name元素:
{
"other-value": "some-id",
"values": [
{
"name": "test-2017-12-01",
"id": "1"
},
{
"name": "othert",
"id": "2"
}
]
}
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以下jq命令可用于jqplay
jq (.values[] | select(.name == "test-afs").id) |= "NEWID"
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但是,当我尝试使用startswith它停止工作时,我缺少什么呢?jqplay
(.values[] | select(.name | startswith("test")).id) |= "NEWID"
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jq:错误(处:14):尝试访问{“ name”:“ test-afs”,“ id”:“ id”}的元素“ id”附近的无效路径表达式退出状态5
您也可以这样使用map:
jq '(.values)|=(map((if .name|startswith("test") then .id="NEWID" else . end)))' file
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输出:
{
"other-value": "some-id",
"values": [
{
"name": "test-2017-12-01",
"id": "NEWID"
},
{
"name": "othert",
"id": "2"
}
]
}
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