coo*_*l77 7 python email smtplib
我正在尝试使用以下代码发送电子邮件.
import smtplib
from email.mime.text import MIMEText
sender = 'sender@sender.com'
def mail_me(cont, receiver):
msg = MIMEText(cont, 'html')
recipients = ",".join(receiver)
msg['Subject'] = 'Test-email'
msg['From'] = "XYZ ABC"
msg['To'] = recipients
# Send the message via our own SMTP server.
try:
s = smtplib.SMTP('localhost')
s.sendmail(sender, receiver, msg.as_string())
print "Successfully sent email"
except SMTPException:
print "Error: unable to send email"
finally:
s.quit()
cont = """\
<html>
<head></head>
<body>
<p>Hi!<br>
How are you?<br>
Here is the <a href="http://www.google.com">link</a> you wanted.
</p>
</body>
</html>
"""
mail_me(cont,['xyz@xyzcom'])
我希望"XYZ ABC"在收到电子邮件时显示为发件人姓名,其电子邮件地址为"sender@sender.com".但是当我收到电子邮件时,我收到了电子邮件"来自"字段中的奇怪细节.
[![from: XYZ@<machine-hostname-appearing-here>
reply-to: XYZ@<machine-hostname-appearing-here>,
ABC@<machine-hostname-appearing-here>][1]][1]
我附上了收到的电子邮件的屏幕截图.
我怎么能根据我的需要解决这个问题.
Mat*_*ido 17
这应该工作:
msg['From'] = "Your name <Your email>"
示例如下:
import smtplib
from email.mime.text import MIMEText
def send_email(to=['example@example.com'], f_host='example.example.com',
f_port=587, f_user='example@example.com', f_passwd='example-pass',
subject='default subject', message='content message'):
smtpserver = smtplib.SMTP(f_host, f_port)
smtpserver.ehlo()
smtpserver.starttls()
smtpserver.ehlo
smtpserver.login(f_user, f_passwd) # from email credential
msg = MIMEText(message, 'html')
msg['Subject'] = 'My custom Subject'
msg['From'] = "Your name <Your email>"
msg['To'] = ','.join(to)
for t in to:
smtpserver.sendmail(f_user, t, msg.as_string()) # you just need to add
this in for loop in your code.
smtpserver.close()
print('Mail is sent successfully!!')
cont = """\
<html>
<head></head>
<body>
<p>Hi!<br>
How are you?<br>
Here is the <a href="http://www.google.com">link</a> you wanted.
</p>
</body>
</html>
"""
try:
send_email(message=cont)
except:
print('Mail could not be sent')
这应该可以修复它：
mail_me(cont,['xyz@xyzcom'])
用。。。来代替
mail_me(cont,'xyz@xyz.com')
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