安卓:java.util.concurrent.ThreadPoolExecutor中

und*_*ned 9 multithreading android

在我的应用程序中有RecyclerView大量的图像.当用户使用以下代码滚动RecyclerView时,会加载图像:

    if(Build.VERSION.SDK_INT >= Build.VERSION_CODES.HONEYCOMB)
        loader.executeOnExecutor(AsyncTask.THREAD_POOL_EXECUTOR,url);
    else
        loader.execute(url);
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不幸的是,有时当用户快速滚动时会发生此错误:

Task android.os.AsyncTask$3@73f1d84 rejected from 
java.util.concurrent.ThreadPoolExecutor@8f5f96d[Running, pool size = 9, 
active threads = 9, queued tasks = 128, completed tasks = 279]
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有没有办法检测poolExecutor是否已满并跳过图像加载?

全图像类:

public class Image extends ImageView {
private AsyncTask<String,Integer,Bitmap> loader;

public Image(Context context) {
    super(context);
    this.setScaleType(ScaleType.FIT_XY);
}

public Image(Context context, AttributeSet attrs) {
    super(context, attrs);
    this.setScaleType(ScaleType.FIT_XY);
}

public void loadURL(String url) {
    if(loader!=null)
        loader.cancel(true);
    loader=new AsyncTask<String, Integer, Bitmap>() {
        @Override
        protected Bitmap doInBackground(String... params) {
            URL url = null;
            byte[] bytes = null;
            HttpURLConnection connection=null;
            try {
                url = new URL(params[0]);
                connection=(HttpURLConnection) url.openConnection();
                connection.setRequestProperty("Connection", "close");
                connection.setRequestMethod("GET");
                connection.setUseCaches(true);
                InputStream is = null;
                is=connection.getInputStream();
                bytes = IOUtils.toByteArray(is);
            } catch (MalformedURLException e) {
                e.printStackTrace();
            } catch (ProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
            if (connection!=null)
                connection.disconnect();
            Bitmap res=null;
            if(!isCancelled() && bytes!=null)
                res=BitmapFactory.decodeByteArray(bytes,0,bytes.length);
            return res;
        }
        @Override
        protected void onPostExecute(Bitmap res) {
            if(res!=null) {
                setImageBitmap(res);
                _animate();
            }
        }
    };
    if (this.getDrawable()!=null) {
        Bitmap bmp=((BitmapDrawable) this.getDrawable()).getBitmap();
        this.setAnimation(null);
        if (bmp!=null) {
            bmp.recycle();
            //Log.d("image","recycled");
        }
        this.setImageBitmap(null);
    }
    /*
    ThreadPoolExecutor e =(ThreadPoolExecutor) Executors.newFixedThreadPool(9);
    Log.d("pool size",e.getActiveCount()+"/"+e.getMaximumPoolSize());
    if (e.getActiveCount() == e.getMaximumPoolSize()) {
    }
    */
    //start loading
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.HONEYCOMB)
        loader.executeOnExecutor(AsyncTask.THREAD_POOL_EXECUTOR, url);
    else
        loader.execute(url);
}
private void _animate() {
    ValueAnimator bgAnim= ValueAnimator.ofObject(new IntEvaluator(),0,255);
    bgAnim.setDuration(500);
    bgAnim.addUpdateListener(new ValueAnimator.AnimatorUpdateListener() {
        @Override
        public void onAnimationUpdate(ValueAnimator animation) {
            Image.this.getDrawable().setAlpha((int) (animation.getAnimatedValue()));
        }
    });
    bgAnim.start();
}
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}

Bud*_*ius 7

我之前回答(这里,这里,这里这里,可能是其他人),我再次为你回答:不要试图重新发明轮子!

图像加载/缓存在Android中是一项非常复杂的任务,许多优秀的开发人员已经这样做了.线程只是其中一个问题,但我可以从你的代码中看到你有内存泄漏,没有缓存,所以你再次重新下载图像,如果回滚到它,HttpURLConnection是一个糟糕的网络层.

所以,解决这个问题的方法(恕我直言)只是重复使用其他开发人员完成的工作.您应该考虑的库的好例子是:

毕加索是我最喜欢的,所以要使用它你只需要打电话:

Picasso.with(context).load(url).into(imgView);
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这一切都是为你处理的.


und*_*ned 3

我刚刚意识到我可以用 try/catch 包装加载代码:

try {
     if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.HONEYCOMB)
            loader.executeOnExecutor(AsyncTask.THREAD_POOL_EXECUTOR, url);
        else
            loader.execute(url);
    } catch (RejectedExecutionException e){
        e.printStackTrace();
}
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看起来这将是可选的解决方案。