根据1列的变化值排名记录

Question

问:如何根据1列的变化值对记录进行排名？

我有以下数据(https://pastebin.com/vdTb1JRT):

EmployeeID  Date        Onleave
ABH12345    2016-01-01  0
ABH12345    2016-01-02  0
ABH12345    2016-01-03  0
ABH12345    2016-01-04  0
ABH12345    2016-01-05  0
ABH12345    2016-01-06  0
ABH12345    2016-01-07  0
ABH12345    2016-01-08  0
ABH12345    2016-01-09  0
ABH12345    2016-01-10  1
ABH12345    2016-01-11  1
ABH12345    2016-01-12  1
ABH12345    2016-01-13  1
ABH12345    2016-01-14  0
ABH12345    2016-01-15  0
ABH12345    2016-01-16  0
ABH12345    2016-01-17  0

我想产生以下结果:

 EmployeeID DateValidFrom    DateValidTo     OnLeave
 ABH12345   2016-01-01       2016-01-09      0
 ABH12345   2016-01-10       2016-01-13      1
 ABH12345   2016-01-14       2016-01-17      0

所以我想我是否可以以某种方式创建一个排名列(如下所示),该列根据Onleave列中的值递增 - 由EmployeeID列分区.

EmployeeID  Date        Onleave    RankedCol
ABH12345    2016-01-01  0          1
ABH12345    2016-01-02  0          1
ABH12345    2016-01-03  0          1
ABH12345    2016-01-04  0          1
ABH12345    2016-01-05  0          1
ABH12345    2016-01-06  0          1
ABH12345    2016-01-07  0          1
ABH12345    2016-01-08  0          1
ABH12345    2016-01-09  0          1
ABH12345    2016-01-10  1          2
ABH12345    2016-01-11  1          2
ABH12345    2016-01-12  1          2
ABH12345    2016-01-13  1          2
ABH12345    2016-01-14  0          3
ABH12345    2016-01-15  0          3
ABH12345    2016-01-16  0          3
ABH12345    2016-01-17  0          3

然后我就能做到以下几点:

SELECT
 [EmployeeID]    = [EmployeeID]
,[DateValidFrom] = MIN([Date])
,[DateValidTo]   = MAX([Date])
,[OnLeave]       = [OnLeave]
FROM table/view/cte/sub-query
GROUP BY 
 [EmployeeID]
,[OnLeave]
,[RankedCol]

其他解决方案非常受欢迎..

以下是测试数据:

WITH CTE AS ( SELECT EmployeeID = 'ABH12345', [Date] = CAST(N'2016-01-01' AS Date), [Onleave] = 0
UNION SELECT 'ABH12345', CAST(N'2016-01-02' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-03' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-04' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-05' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-06' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-07' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-08' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-09' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-10' AS Date), 1
UNION SELECT 'ABH12345', CAST(N'2016-01-11' AS Date), 1
UNION SELECT 'ABH12345', CAST(N'2016-01-12' AS Date), 1
UNION SELECT 'ABH12345', CAST(N'2016-01-13' AS Date), 1
UNION SELECT 'ABH12345', CAST(N'2016-01-14' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-15' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-16' AS Date), 0
UNION SELECT 'ABH12345', CAST(N'2016-01-17' AS Date), 0
)

SELECT * FROM CTE

Answer 1

这是另一种更简单的方法来获得所需的输出 - 仅访问该表一次。

-- sample of data from your question
with t1(EmployeeID, Date1, Onleave) as(
  select 'ABH12345', cast('2016-01-01' as date),  0 union all
  select 'ABH12345', cast('2016-01-02' as date),  0 union all
  select 'ABH12345', cast('2016-01-03' as date),  0 union all
  select 'ABH12345', cast('2016-01-04' as date),  0 union all
  select 'ABH12345', cast('2016-01-05' as date),  0 union all
  select 'ABH12345', cast('2016-01-06' as date),  0 union all
  select 'ABH12345', cast('2016-01-07' as date),  0 union all
  select 'ABH12345', cast('2016-01-08' as date),  0 union all
  select 'ABH12345', cast('2016-01-09' as date),  0 union all
  select 'ABH12345', cast('2016-01-10' as date),  1 union all
  select 'ABH12345', cast('2016-01-11' as date),  1 union all
  select 'ABH12345', cast('2016-01-12' as date),  1 union all
  select 'ABH12345', cast('2016-01-13' as date),  1 union all
  select 'ABH12345', cast('2016-01-14' as date),  0 union all
  select 'ABH12345', cast('2016-01-15' as date),  0 union all
  select 'ABH12345', cast('2016-01-16' as date),  0 union all
  select 'ABH12345', cast('2016-01-17' as date),  0
)
-- actual query
select max(w.employeeid) as employeeid
     , min(w.date1)      as datevalidfrom
     , max(w.date1)      as datevalidto
     , max(w.onleave)    as onleave 
  from (
        select row_number() over(partition by employeeid order by date1) -
               row_number() over(partition by employeeid, onleave order by date1) as grp
             , employeeid
             , date1
             , onleave
          from t1 s
        ) w
group by w.grp
order by employeeid, datevalidfrom

结果：

employeeid datevalidfrom datevalidto onleave
---------- ------------- ----------- -----------
ABH12345   2016-01-01    2016-01-09  0
ABH12345   2016-01-10    2016-01-13  1
ABH12345   2016-01-14    2016-01-17  0