IQueryable <T> .Where()适合表达式在哪里?

PaN*_*1Me 3 .net c# lambda expression

Expressions在.NET中经验很少,这就是为什么我宁愿问你们.我该怎么做 - 看下面的评论:

using P = Myclass;
..
System.Linq.Expressions.Expression<Func<P, bool>> myExpression = null;
..
myExpression1 = x => foo1 == true && foo2 == false;
myExpression2 = x => ... ;
..
BinaryExpression resultExpression = System.Linq.Expressions.Expression.OrElse(myExpression1, myExpression2);
..
IQueryable<P> l = l.Where(?resultExpression?); // how to transform BinaryExpression to the suitable type?
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谢谢

Amy*_*y B 5

你不能用这种方式"或"羔羊.你真的想把lambda体"和"在一起.这是一种方法:

public static Expression<Func<T, bool>> OrTheseFiltersTogether<T>( 
  this IEnumerable<Expression<Func<T, bool>>> filters) 
{ 
    Expression<Func<T, bool>> firstFilter = filters.FirstOrDefault(); 
    if (firstFilter == null) 
    { 
        Expression<Func<T, bool>> alwaysTrue = x => true; 
        return alwaysTrue; 
    } 

    var body = firstFilter.Body; 
    var param = firstFilter.Parameters.ToArray(); 
    foreach (var nextFilter in filters.Skip(1)) 
    { 
        var nextBody = Expression.Invoke(nextFilter, param); 
        body = Expression.OrElse(body, nextBody); 
    } 
    Expression<Func<T, bool>> result = Expression.Lambda<Func<T, bool>>(body, param); 
    return result; 
} 
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然后呢:

Expression<Func<P, bool>> myFilter1 = x => foo1 == true && foo2 == false;  
Expression<Func<P, bool>> myFilter2 = x => ... ;  
..  
List<Expression<Func<P, bool>>> filters = new List<Expression<Func<P, bool>>>();
filters.Add(myfilter1);
filters.Add(myfilter2);
..  
Expression<Func<P, bool>> resultFilter = filters.OrTheseFiltersTogether();
IQueryable<P> query = query.Where(resultFilter);
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