Gui*_*tue 3 java jersey jackson
我在java Rest Api中使用Jackson来处理请求参数.
我的班级:
public class ZoneModifBeanParam extends ModifBeanParam<Zone> {
@FormParam("type")
private String type;
@FormParam("geometry")
private Geometry geometry;
@FormParam("name")
private String name;
...
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我的API界面:
@POST
@Consumes("application/json")
@Produces("application/json; subtype=geojson")
@ApiOperation(value = "Create a zone", notes = "To create a zone")
public Response createZone(ZoneModifBeanParam zoneParam) {
...
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这工作正常,但我需要接收我的Bean在地图中未指定的其他参数.示例:
{
"geometry": {...},
"name": "A circle name",
"type": "4",
"hello": true
}
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通过接收这个我需要存储在一个Map(名为unrecognizedFields并在我的bean中声明)这对夫妇("你好",真实).
是否有任何注释或对象允许这个?
只需使用@JsonAnySetter.这就是它的目的.这是一个测试用例
public class JacksonTest {
public static class Bean {
private String name;
public String getName() { return this.name; }
public void setName(String name) { this.name = name; }
private Map<String, Object> unrecognizedFields = new HashMap<>();
@JsonAnyGetter
public Map<String, Object> getUnrecognizedFields() {
return this.unrecognizedFields;
}
@JsonAnySetter
public void setUnrecognizedFields(String key, Object value) {
this.unrecognizedFields.put(key, value);
}
}
private final String json
= "{\"name\":\"paul\",\"age\":600,\"nickname\":\"peeskillet\"}";
private final ObjectMapper mapper = new ObjectMapper();
@Test
public void testDeserialization() throws Exception {
final Bean bean = mapper.readValue(json, Bean.class);
final Map<String, Object> unrecognizedFields = bean.getUnrecognizedFields();
assertEquals("paul", bean.getName());
assertEquals(600, unrecognizedFields.get("age"));
assertEquals("peeskillet", unrecognizedFields.get("nickname"));
}
}
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将@JsonAnyGetter
被用在序列化侧.序列化bean时,您将看不到unrecognizedFields
JSON中的内容.相反,地图中的所有属性都将序列化为JSON中的顶级属性.
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