Cla*_*dio 36 sqlite string date date-format
我将日期存储为sqlite数据库中的字符串,如"28/11/2010".我想将字符串转换为日期.
具体来说,我必须在两个日期之间转换大量的字符串日期.
在postgresql中,我使用to_date('30/11/2010','dd/MM/yyyy')
,如何用sqlite做同样的事情?
像这样的东西:
SELECT * FROM table
WHERE to_date(column,'dd/MM/yyyy')
BETWEEN to_date('01/11/2010','dd/MM/yyyy')
AND to_date('30/11/2010','dd/MM/yyyy')
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小智 65
由于Sqlite 没有日期类型,您需要进行字符串比较才能实现此目的.要做到这一点你需要扭转顺序 - 例如从dd/MM/yyyy到yyyyMMdd,使用像
where substr(column,7)||substr(column,4,2)||substr(column,1,2)
between '20101101' and '20101130'
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小智 18
保存日期为TEXT(20/10/2013 03:26)要进行查询并在日期之间选择记录?
更好的版本是:
SELECT TIMSTARTTIMEDATE
FROM TIMER
WHERE DATE(substr(TIMSTARTTIMEDATE,7,4)
||substr(TIMSTARTTIMEDATE,4,2)
||substr(TIMSTARTTIMEDATE,1,2))
BETWEEN DATE(20131020) AND DATE(20131021);
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2013年10月20日的substr给出了20131020日期格式DATE(20131021) - 这使得SQL使用日期并使用日期和时间函数.
要么
SELECT TIMSTARTTIMEDATE
FROM TIMER
WHERE DATE(substr(TIMSTARTTIMEDATE,7,4)
||'-'
||substr(TIMSTARTTIMEDATE,4,2)
||'-'
||substr(TIMSTARTTIMEDATE,1,2))
BETWEEN DATE('2013-10-20') AND DATE('2013-10-21');
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这是一行
SELECT TIMSTARTTIMEDATE FROM TIMER WHERE DATE(substr(TIMSTARTTIMEDATE,7,4)||'-'||substr(TIMSTARTTIMEDATE,4,2)||'-'||substr(TIMSTARTTIMEDATE,1,2)) BETWEEN DATE('2013-10-20') AND DATE('2013-10-21');
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MPe*_*ier 10
你应该研究的一件事是SQLite日期和时间函数,特别是如果你将不得不操纵很多日期.这是使用日期的理智方式,代价是更改内部格式(必须是ISO,即yyyy-MM-dd).
与脆性相比,UDF 方法是我的首选 substr
值。
#!/usr/bin/env python3
import sqlite3
from dateutil import parser
from pprint import pprint
def date_parse(s):
''' Converts a string to a date '''
try:
t = parser.parse(s, parser.parserinfo(dayfirst=True))
return t.strftime('%Y-%m-%d')
except:
return None
def dict_factory(cursor, row):
''' Helper for dict row results '''
d = {}
for idx, col in enumerate(cursor.description):
d[col[0]] = row[idx]
return d
def main():
''' Demonstrate UDF '''
with sqlite3.connect(":memory:") as conn:
conn.row_factory = dict_factory
setup(conn)
##################################################
# This is the code that matters. The rest is setup noise.
conn.create_function("date_parse", 1, date_parse)
cur = conn.cursor()
cur.execute(''' select "date", date_parse("date") as parsed from _test order by 2; ''')
pprint(cur.fetchall())
##################################################
def setup(conn):
''' Setup some values to parse '''
cur = conn.cursor()
# Make a table
sql = '''
create table _test (
"id" integer primary key,
"date" text
);
'''
cur.execute(sql)
# Fill the table
dates = [
'2/1/03', '03/2/04', '4/03/05', '05/04/06',
'6/5/2007', '07/6/2008', '8/07/2009', '09/08/2010',
'2-1-03', '03-2-04', '4-03-05', '05-04-06',
'6-5-2007', '07-6-2008', '8-07-2009', '09-08-2010',
'31/12/20', '31-12-2020',
'BOMB!',
]
params = [(x,) for x in dates]
cur.executemany(''' insert into _test ("date") values(?); ''', params)
if __name__ == "__main__":
main()
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这将为您提供以下结果:
[{'date': 'BOMB!', 'parsed': None},
{'date': '2/1/03', 'parsed': '2003-01-02'},
{'date': '2-1-03', 'parsed': '2003-01-02'},
{'date': '03/2/04', 'parsed': '2004-02-03'},
{'date': '03-2-04', 'parsed': '2004-02-03'},
{'date': '4/03/05', 'parsed': '2005-03-04'},
{'date': '4-03-05', 'parsed': '2005-03-04'},
{'date': '05/04/06', 'parsed': '2006-04-05'},
{'date': '05-04-06', 'parsed': '2006-04-05'},
{'date': '6/5/2007', 'parsed': '2007-05-06'},
{'date': '6-5-2007', 'parsed': '2007-05-06'},
{'date': '07/6/2008', 'parsed': '2008-06-07'},
{'date': '07-6-2008', 'parsed': '2008-06-07'},
{'date': '8/07/2009', 'parsed': '2009-07-08'},
{'date': '8-07-2009', 'parsed': '2009-07-08'},
{'date': '09/08/2010', 'parsed': '2010-08-09'},
{'date': '09-08-2010', 'parsed': '2010-08-09'},
{'date': '31/12/20', 'parsed': '2020-12-31'},
{'date': '31-12-2020', 'parsed': '2020-12-31'}]
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SQLite 等价于任何这种健壮的东西是你应该避免的混乱的编织substr
和instr
调用。