我试图从Beginning C 5th Ed这本书编译一个示例程序.作者:Ivor Horton.试图在OSX上编译它,我从gcc获得以下输出:
$ gcc program6_07.c
program6_07.c:18:59: warning: format specifies type 'int' but the argument has
type 'size_t' (aka 'unsigned long') [-Wformat]
"Terminate input by entering an empty line:\n", str_len);
^~~~~~~
program6_07.c:23:5: warning: implicit declaration of function 'gets_s' is
invalid in C99 [-Wimplicit-function-declaration]
gets_s(buf, buf_len); // Read a lin...
^
program6_07.c:24:9: warning: implicit declaration of function 'strnlen_s' is
invalid in C99 [-Wimplicit-function-declaration]
if(!strnlen_s(buf, buf_len)) // Empty lin...
^
program6_07.c:27:8: warning: implicit declaration of function 'strcat_s' is
invalid in C99 [-Wimplicit-function-declaration]
if(strcat_s(str, str_len, buf)) // Concatenat...
^
program6_07.c:33:60: warning: data argument not used by format string
[-Wformat-extra-args]
printf("The words in the prose that you entered are:\n", str);
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ^
program6_07.c:37:18: warning: implicit declaration of function 'strtok_s' is
invalid in C99 [-Wimplicit-function-declaration]
char * pWord = strtok_s(str, &str_len, delimiters, &ptr); // Find 1st word
^
program6_07.c:37:10: warning: incompatible integer to pointer conversion
initializing 'char *' with an expression of type 'int' [-Wint-conversion]
char * pWord = strtok_s(str, &str_len, delimiters, &ptr); // Find 1st word
^ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
program6_07.c:45:13: warning: incompatible integer to pointer conversion
assigning to 'char *' from 'int' [-Wint-conversion]
pWord = strtok_s(NULL, &str_len, delimiters, &ptr); // Find sub...
^ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
8 warnings generated.
Undefined symbols for architecture x86_64:
"_gets_s", referenced from:
_main in program6_07-4a1c4c.o
"_strcat_s", referenced from:
_main in program6_07-4a1c4c.o
"_strnlen_s", referenced from:
_main in program6_07-4a1c4c.o
"_strtok_s", referenced from:
_main in program6_07-4a1c4c.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
Run Code Online (Sandbox Code Playgroud)
该计划的代码如下:
// Program 6.7 Find all the words
#define __STDC_WANT_LIB_EXT1__ 1 // Make optional versions of functions available
#include <stdio.h>
#include <string.h>
#include <stdbool.h>
int main(void)
{
char delimiters[] = " \".,;:!?)("; // Prose delimiters
char buf[100]; // Buffer for a line of keyboard input
char str[1000]; // Stores the prose to be tokenized
char* ptr = NULL; // Pointer used by strtok_s()
str[0] = '\0'; // Set 1st character to null
size_t str_len = sizeof(str);
size_t buf_len = sizeof(buf);
printf("Enter some prose that is less than %d characters.\n"
"Terminate input by entering an empty line:\n", str_len);
// Read multiple lines of prose from the keyboard
while(true)
{
gets_s(buf, buf_len); // Read a line of input
if(!strnlen_s(buf, buf_len)) // Empty line ends input
break;
if(strcat_s(str, str_len, buf)) // Concatenate the line with str
{
printf("Maximum permitted input length exceeded.");
return 1;
}
}
printf("The words in the prose that you entered are:\n", str);
// Find and list all the words in the prose
unsigned int word_count = 0;
char * pWord = strtok_s(str, &str_len, delimiters, &ptr); // Find 1st word
if(pWord)
{
do
{
printf("%-18s", pWord);
if(++word_count % 5 == 0)
printf("\n");
pWord = strtok_s(NULL, &str_len, delimiters, &ptr); // Find subsequent words
}while(pWord); // NULL ends tokenizing
printf("\n%u words found.\n", word_count);
}
else
printf("No words found.\n");
return 0;
}
Run Code Online (Sandbox Code Playgroud)
我以为我已经定义了可选功能,但我想我没有?这只是一本陈旧的书或一个坏的例子,还是我在尝试编译时做错了什么?
该gets_s()
功能在ISO/IEC 9899:2011的附录K,当前的C标准和TR 24731-1中定义.这是可选的.它没有被广泛实现 - 事实上,它基本上只能在使用Microsoft C库的Microsoft系统上使用.类似的评论适用于其他_s
功能 - 它们在附录K中定义,除了微软的编译器外,通常不会在任何地方实现.
请注意,您可以通过测试是否__STDC_LIB_EXT1__
由编译器设置来测试附件K函数在一般情况下是否可用.它应具有200509L
与原始TR 24731-1一致的值或201112L
符合附件K.如果由实现定义,则您的代码应定义__STDC_WANT_LIB_EXT1__
为暴露附件K功能的定义.
您将需要使用不同的功能:
gets_s()
,标准fgets()
可能是最接近的,但它包括输入末尾的换行符,而gets_s()
不是.另外,gets_s()
在错误上截断输出字符串 - 如果在没有剩余空格之前没有换行符; 如果发生这种情况,它也会读到下一个换行符.该fgets()
功能不会执行任何操作.strnlen_s()
,使用strnlen()
,可在macOS Sierra(和Mac OS X)和Linux上使用.strcat_s()
,可能使用strlcat()
,再次在macOS Sierra和Linux上可用.strtok_s()
,可能使用strtok_r()
,这是POSIX的标准部分.请注意,接口与接口strtok_r()
不同strtok_s()
,但功能基本相同.