线程中django的call_command问题

Question

我想在Thread中执行django的call_method.这是示例代码:

import sys
sys.path.append("/my/django/project/path/")
import threading
import time 


# Import my django project configuration settings
from django.core.management import setup_environ
from mydjangoprojectname import settings
setup_environ(settings)

from django.core.management import call_command

class ServerStarter(threading.Thread):
    def __init__(self):
        super(ServerStarter, self).__init__()
        print "ServerStarter instance created"

    def run(self):
        print "Starting Django Server..."
        call_command("runserver", noreload=True)


if __name__ == '__main__':
    starter = ServerStarter()
    starter.start()

------------------------------
OutPut:
ServerStarter instance created
Starting Django Server...
ServerStarter instance created
Starting Django Server...
Validating models...
0 errors found
Django version 1.2.3, using settings 'mydjangoprojectname.settings'
Development server is running at http://127.0.0.1:8000/
Quit the server with CONTROL-C.

Django服务器正常启动,但ServerStarter创建了两次.
两个ServerStarter的实例都运行了.
如果我在run方法中注释call_command("runserver",noreload = True),那么只
创建一个线程(这就是我想要的).
提前致谢!

Answer 1

我找到了解决方案(克里斯摩根是对的).这段代码按我的意思运行:

import sys
sys.path.append("/my/django/project/path/")
import threading

# Import my django project configuration settings
from django.core.management import setup_environ, ManagementUtility

from mydjangoprojectname import settings
setup_environ(settings)


class ServerStarter(threading.Thread):
    def __init__(self):
        super(ServerStarter, self).__init__()
        print "ServerStarter instance created"

    def run(self):
        print "Starting Django Server..."
        utility = ManagementUtility()
        command = utility.fetch_command('runserver')
        command.execute(use_reloader=False)


if __name__ == '__main__':
    starter = ServerStarter()
    starter.start()