我正在尝试处理 XML 文件,但出现此错误:
XPathEvalError: Undefined namespace prefix
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在这一行:
print "category =", item.xpath("./g:google_product_category")
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这是 XML 文件:
<rss xmlns:g="http://base.google.com/ns/1.0" version="2.0">
<channel>
<title>example.net.br</title>
<link>http://www.example.net.br/</link>
<description>Data feed description.</description>
<item>
<title>
<![CDATA[
example
]]>
</title>
<link>
<![CDATA[
example
]]>
</link>
<description>
<![CDATA[
example]]>
</description>
<g:google_product_category>
<![CDATA[
example
]]>
</g:google_product_category>
...
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这是我的代码:
headers = { 'User-Agent' : 'Mozilla/5.0' }
req = urllib2.Request(feed_url, None, headers)
file = urllib2.urlopen(req).read()
file = etree.fromstring(file)
for item in file.xpath('/rss/channel/item'):
print "title =", item.xpath("./title/text()")[0]
print "link =", item.xpath("./link/text()")[0]
print "description =", item.xpath("./description/text()")[0]
print "category =", item.xpath("./g:google_product_category")
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我怎样才能解决这个问题?
xpath 方法接受一个额外的参数:命名空间
您能否尝试如下修改该行:
print "category =", item.xpath("./g:google_product_category", namespaces={'g': 'http://base.google.com/ns/1.0'})
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