Python 进程池执行器根据信号关闭

Question

我使用主管来运行一些这样的脚本。因此，当主管停止或中断时，我尝试优雅地退出脚本。这是我当前的代码

import concurrent.futures
import random
import os
import signal
import sys

executor = concurrent.futures.ProcessPoolExecutor(max_workers=2)

some_flag = True

def some_func():
    while some_flag:
        executor.submit(print_some_num)

def print_some_num():
    print("From worker :{}".format(os.getpid()))
    print(random.randint(0,10))

def handler(arg1, arg2):
    print("Got interrupt")
    some_flag = False
    sys.exit("Run for ur life")
    #executor.shutdown(wait = False) ----> not working
    print("Shutdown")

signal.signal(signal.SIGTERM,handler)
signal.signal(signal.SIGINT,handler)

if __name__ == '__main__':
    some_func()

这工作正常，现在当我读到 executor.shutdown(wait=True/False) 时我很困惑。所以我尝试了一下，但无法让执行程序关闭（它只是挂起）。请帮我解答这些问题

 1) what does executor.shutdown do that sys.exit() doesn't do.
 2) What is advisable in production environment? If executor shutdown is required, please help me fix the issue with shutdown. 

Answer 1

1）显然， shutdown 停止了所有正在处理的现有消息，但 sys.exit() 刚刚出现。（在文档中https://docs.python.org/3/library/concurrent.futures.html）

2）如果有人卡在同一个地方，使用一些全局变量来发出关闭信号。

def some_func():
with concurrent.futures.ProcessPoolExecutor(max_workers=2) as executor:
    while True:
        global some_flag
        print(some_flag)
        if not some_flag:
            executor.shutdown(wait=True)
            sys.exit()
        else:
            executor.submit(print_some_num)

def print_some_num():
    print("From worker :{}".format(os.getpid()))
    print(random.randint(0,10))

def handler(arg1, arg2):
    global some_flag
    print("Got interrupt")
    some_flag = False
    print("Shutdown")

signal.signal(signal.SIGTERM,handler)
signal.signal(signal.SIGINT,handler)