luk*_*hol 6 c# asp.net-web-api swagger
我有休息控制器,它以流文件作为内容返回 HttpResponseMessage,如下所示:
public class MyController : ApiController
{
public HttpResponseMessage GetFile(string id)
{
try {
var stream = fileSystemUtils.GetFileStream(filePath); //Get Stream
HttpResponseMessage response = new HttpResponseMessage(HttpStatusCode.OK);
response.Content = stream;
return response;
}
catch (FileNotFoundException)
{
return new HttpResponseMessage(HttpStatusCode.NotFound);
}
}
}
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当我在浏览器中通过 ULR 调用此方法时,一切正常,我可以下载此文件。现在我想使用 Swagger UI 下载它。有什么简单的方法可以做到这一点吗?
这对我有用(.Net Core 2.2 和 Swashbuckle 4.0.1):
[Route("api/[controller]")]
[ApiController]
public class DownloadController : ControllerBase
{
[HttpGet("{name}")]
[ProducesResponseType(typeof(byte[]), StatusCodes.Status200OK)]
[ProducesResponseType(typeof(BadRequestObjectResult), 400)]
public async Task<IActionResult> GetFile(string fileName)
{
var filePath = $"files/{fileName}"; // get file full path based on file name
if (!System.IO.File.Exists(filePath))
{
return BadRequest();
}
return File(await System.IO.File.ReadAllBytesAsync(filePath), "application/octet-stream", fileName);
}
}
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如果其他人正在寻找这个,我做了以下事情:
public class FileOperation : IOperationFilter
{
public void Apply(Operation operation, OperationFilterContext context)
{
if (operation.OperationId.ToLower() == "apifileget")
{
operation.Produces = new[] { "application/octet-stream" };
operation.Responses["200"].Schema = new Schema { Type = "file", Description = "Download file"};
}
}
}
//In the startup...
services.AddSwaggerGen(c =>
{
//missing code...
c.OperationFilter<FileOperation>();
});
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