在html表中转置/交换x,y轴

Question

我有一个需要旋转/轴交换的html表.它可以脱机完成.任何人都知道我可以使用的工具吗？

Answer 1

这种转变:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes"/>

 <xsl:template match="table">
     <xsl:for-each select="tr[1]/td">
      <xsl:variable name="vRowPos" select="position()"/>
      <tr>
       <xsl:for-each select="/table/tr">
        <xsl:variable name="vColPos" select="position()"/>
        <xsl:copy-of select="/table/tr[$vColPos]/td[$vRowPos]"/>
       </xsl:for-each>
      </tr>
     </xsl:for-each>
 </xsl:template>
</xsl:stylesheet>

应用于此XML文档时:

<table>
 <tr>
  <td>A11</td>
  <td>A12</td>
  <td>A13</td>
  <td>A14</td>
  <td>A15</td>
 </tr>
 <tr>
  <td>A21</td>
  <td>A22</td>
  <td>A23</td>
  <td>A24</td>
  <td>A25</td>
 </tr>
 <tr>
  <td>A31</td>
  <td>A32</td>
  <td>A33</td>
  <td>A34</td>
  <td>A35</td>
 </tr>
</table>

产生想要的,正确的结果:

<table>
    <tr>
        <td>A11</td>
        <td>A21</td>
        <td>A31</td>
    </tr>
    <tr>
        <td>A12</td>
        <td>A22</td>
        <td>A32</td>
    </tr>
    <tr>
        <td>A13</td>
        <td>A23</td>
        <td>A33</td>
    </tr>
    <tr>
        <td>A14</td>
        <td>A24</td>
        <td>A34</td>
    </tr>
    <tr>
        <td>A15</td>
        <td>A25</td>
        <td>A35</td>
    </tr>
</table>

请注意:假设表格具有 规则结构.