使用Jackson和Json-View排除json中的字段

Dev*_*Dev 12 java json jackson json-view

我正在使用json-view根据我的需要创建一个动态json,它是一个很棒的库,我现在正在使用这个库一段时间.最近我遇到了一个使用案例的问题,让我先放置我的代码

用户类

public class User {

    private String name;
    private String emailId;
    private String mobileNo;

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getEmailId() {
        return emailId;
    }

    public void setEmailId(String emailId) {
        this.emailId = emailId;
    }

    public String getMobileNo() {
        return mobileNo;
    }

    public void setMobileNo(String mobileNo) {
        this.mobileNo = mobileNo;
    }

}
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ScreenInfoPojo类

public class ScreenInfoPojo {

    private Long id;
    private String name;
    private ScreenInfoPojo parentScreen;
    private User createdBy;
    private User lastUpdatedBy;

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public ScreenInfoPojo getParentScreen() {
        return parentScreen;
    }

    public void setParentScreen(ScreenInfoPojo parentScreen) {
        this.parentScreen = parentScreen;
    }



    public User getCreatedBy() {
        return createdBy;
    }

    public void setCreatedBy(User createdBy) {
        this.createdBy = createdBy;
    }

    public User getLastUpdatedBy() {
        return lastUpdatedBy;
    }

    public void setLastUpdatedBy(User lastUpdatedBy) {
        this.lastUpdatedBy = lastUpdatedBy;
    } 
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运行代码

public class TestMain {
    public static void main(String[] args) throws JsonProcessingException {
        User user=new User();
        user.setName("ABC");
        user.setEmailId("dev@abc123.com");
        user.setMobileNo("123456789");

        ScreenInfoPojo screen1=new ScreenInfoPojo();
        screen1.setId(1l);
        screen1.setName("Screen1");
        screen1.setCreatedBy(user);
        screen1.setLastUpdatedBy(user);

        ScreenInfoPojo screen2=new ScreenInfoPojo();
        screen2.setId(2l);
        screen2.setName("Screen2");
        screen2.setParentScreen(Screen1);
        screen2.setCreatedBy(user);
        screen2.setLastUpdatedBy(user);

        ScreenInfoPojo screen3=new ScreenInfoPojo();
        screen3.setId(3l);
        screen3.setName("Screen3");
        screen3.setParentScreen(Screen2);
        screen3.setCreatedBy(user);
        screen3.setLastUpdatedBy(user);

        ScreenInfoPojo screen4=new ScreenInfoPojo();
        screen4.setId(4l);
        screen4.setName("Screen4");
        screen4.setParentScreen(Screen3);
        screen4.setCreatedBy(user);
        screen4.setLastUpdatedBy(user);

        List<ScreenInfoPojo> screens=new ArrayList<>();
        screens.add(screen1);
        screens.add(screen2);
        screens.add(screen3);
        screens.add(screen4);

        ObjectMapper mapper = new ObjectMapper().registerModule(new JsonViewModule());
        String json = mapper.writeValueAsString(JsonView.with(screens).onClass(ScreenInfoPojo.class, Match.match()
                .exclude("*")
                .include("id","name","createdBy.name","lastUpdatedBy.mobileNo","parentScreen.id")));
        System.out.println("json"+json);
    }    
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结果

[{
    "id": 1,
    "name": "Screen1",
    "parentScreen": null,
    "createdBy": {
        "name": "ABC"
    },
    "lastUpdatedBy": {
        "mobileNo": "123456789"
    }
}, {
    "id": 2,
    "name": "Screen2",
    "parentScreen": {
        "id": 1,
        "name": "Screen1",
        "parentScreen": null,
        "createdBy": {},
        "lastUpdatedBy": {}
    },
    "createdBy": {
        "name": "ABC"
    },
    "lastUpdatedBy": {
        "mobileNo": "123456789"
    }
}, {
    "id": 3,
    "name": "Screen3",
    "parentScreen": {
        "id": 2,
        "name": "Screen2",
        "parentScreen": {
            "id": 1,
            "name": "Screen1",
            "parentScreen": null,
            "createdBy": {},
            "lastUpdatedBy": {}
        },
        "createdBy": {},
        "lastUpdatedBy": {}
    },
    "createdBy": {
        "name": "ABC"
    },
    "lastUpdatedBy": {
        "mobileNo": "123456789"
    }
}, {
    "id": 4,
    "name": "Screen4",
    "parentScreen": {
        "id": 3,
        "name": "Screen3",
        "parentScreen": {
            "id": 2,
            "name": "Screen2",
            "parentScreen": {
                "id": 1,
                "name": "Screen1",
                "parentScreen": null,
                "createdBy": {},
                "lastUpdatedBy": {}
            },
            "createdBy": {},
            "lastUpdatedBy": {}
        },
        "createdBy": {},
        "lastUpdatedBy": {}
    },
    "createdBy": {
        "name": "ABC"
    },
    "lastUpdatedBy": {
        "mobileNo": "123456789"
    }
}]
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预期结果

[{
    "id": 1,
    "name": "Screen1",
    "parentScreen": null,
    "createdBy": {
        "name": "ABC"
    },
    "lastUpdatedBy": {
        "mobileNo": "123456789"
    }
}, {
    "id": 2,
    "name": "Screen2",
    "parentScreen": {
        "id": 1
    },
    "createdBy": {
        "name": "ABC"
    },
    "lastUpdatedBy": {
        "mobileNo": "123456789"
    }
}, {
    "id": 3,
    "name": "Screen3",
    "parentScreen": {
        "id": 2
    },
    "createdBy": {
        "name": "ABC"
    },
    "lastUpdatedBy": {
        "mobileNo": "123456789"
    }
}, {
    "id": 4,
    "name": "Screen4",
    "parentScreen": {
        "id": 3
    },
    "createdBy": {
        "name": "ABC"
    },
    "lastUpdatedBy": {
        "mobileNo": "123456789"
    }
}]
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问题

在我的用例中,我有一个类ScreenInfoPojo,它引用与parentScreen相同的类,我试图获取父类的特定字段/字段("parentScreen.id")instate我得到我在child/target对象上定义的所有字段("id","name","createdBy.name","lastUpdatedBy.mobileNo","parentScreen.id")和父响应再次递归!有一点我观察到它只发生在一个类有自己的引用的情况下,我将User类引用作为两个不同的字段createdBylastUpdatedBy并尝试获取"name""mobileNo"分别工作得很好.

任何解决这个问题的建议都会非常有用!!!!

谢谢

Ole*_*leg 3

是的。Include 子句不适用于引用同一类。

你能做到吗?

根据github指令从源代码编译build from source

更新函数 JsonViewSerializer.JsonWriter.fieldAllowed

寻找:

        if(match == null) {
            match = this.currentMatch;
        } else {
            prefix = "";
        }
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和注释 else 子句

        if(match == null) {
            match = this.currentMatch;
        } else {
            //prefix = "";
        }
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您将得到预期的结果。但。我不知道它会如何影响其他过滤器。

要获得更多控制,您可以向 JsonView 类添加属性。

例如:

在 JsonView 添加:

private boolean ignorePathIfClassRegistered = true;

     public boolean isIgnorePathIfClassRegistered() {
            return ignorePathIfClassRegistered;
        }

        public JsonView1<T>  setIgnorePathIfClassRegistered(boolean ignorePathIfClassRegistered) {
            this.ignorePathIfClassRegistered = ignorePathIfClassRegistered;
            return this;
        }
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在 JsonViewSerializer.JsonWriter.fieldAllowed 函数中将 if 子句重写为:

        if(match == null) {
            match = this.currentMatch;
        } else {
            if (result.isIgnorePathIfClassRegistered())
            prefix = "";
        }
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您可以在示例中使用它,例如:

JsonView<List<ScreenInfoPojo>> viwevedObject = JsonView
        .with(screens)
        .onClass(ScreenInfoPojo.class,
                Match.match()
                        .exclude("*")
                        .include("id","name")
                        .include("createdBy.name")
                        .include("lastUpdatedBy.mobileNo")
                        .include("parentScreen.id"))
        .setIgnorePathIfClassRegistered(false);

ObjectMapper mapper = new ObjectMapper().registerModule(new JsonViewModule());
mapper.configure(SerializationFeature.INDENT_OUTPUT, true);

String json = mapper.writeValueAsString(viwevedObject);
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