vuex:未知的getter:user

Question

我正在尝试使用vuex,我正在寻找组织我的vuex文件的最佳方法,我完成了这样的事情:

/src/store/user/state.js:

export default {
  state: {
    user: null
  }
}

/src/store/user/getters.js:

export default {
  getters: {
    user (state) {
      return state.user
    }
  }
}

/src/store/user/mutations.js:

export default {
  mutations: {
    'SET_USER' (state, user) {
      state.user = user
    }
  }
}

/src/store/user/actions.js

export default {
  actions: {
    loginUser ({ commit }, params) {
       commit('SET_USER', {id: 1})
    }
  }
}

/src/store/user/index.js

import state from './state'
import getters from './getters'
import actions from './actions'
import mutations from './mutations'

export default {
  state,
  getters,
  actions,
  mutations
}

/src/store/index.js:

import Vue from 'vue'
import Vuex from 'vuex'
import user from './user'

Vue.use(Vuex)

export default new Vuex.Store({
  modules: {
    user
  }
})

当我加载我的代码时,它会在控制台中返回错误:

vuex: unknown getter: user

Answer 1

每个用户相关的文件正在使用export default,当您导入这些文件,这意味着,你命名整个对象被导出state,getters等等.

因此,在变量的范围内index,state变量具有一个名为的属性state,该getters变量具有一个名为的属性getters等.这就是抛弃它.

您应该const为每个文件导出一个:

export const state = {
  user: null,
}

然后在导入时抓取命名const如下:

import { state } from './state'

或者,你可以只取出的性质state,getters从每个文件,等等:

// state.js
export default {
  user: null,
}

然后导入就像你已经做的那样:

import state from './state'