如果满足lambda条件,则删除整个列表

Question

假设您有一个列表列表:

[[1,2,3,4,5,6],[2,3,4,5,6,7],['a',12,3,4,5,], ['a',123,4,5,6]]

我可以删除(使用lambda)a第一个元素中的列表吗？我开始玩Python的lambda,这已经让我困惑了一段时间.可以吗？

Answer 1

filter从给定列表中删除给定函数返回的元素False.列表推导可以类似地与谓词一起使用.

>>> xss = [[1,2,3,4,5,6],[2,3,4,5,6,7],['a',12,3,4,5,], ['a',123,4,5,6]]
>>> list(filter(lambda xs: len(xs) != 0 and xs[0] != 'a', xss))
[[1, 2, 3, 4, 5, 6], [2, 3, 4, 5, 6, 7]]
>>> [xs for xs in xss if len(xs) != 0 and xs[0] != 'a']
[[1, 2, 3, 4, 5, 6], [2, 3, 4, 5, 6, 7]]