awf*_*fun 5 groovy gradle kotlin
我有一处房产gradle.properties:
answer = 42
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用于build.gradle:
println "answer is ${answer}"
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现在我想用 Kotlin 脚本替换 Groovy 以进行 Gradle 配置。如何以正确的方式访问属性?我现在在做的build.gradle.kts是:
fun property(name: String) = properties[name] as String
println("answer is " + property("answer"))
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这似乎不是很方便。谢谢!
尝试委托属性,如下所示:
val answer by project
println("answer is $answer")
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gradle 脚本 kotlin 存储库中有示例 https://github.com/gradle/gradle-script-kotlin/tree/master/samples/project-properties