目前我正在使用java.nio.file.File.write(Path, Iterable, Charset)编写txt文件。代码在这里...
Path filePath = Paths.get("d:\\myFile.txt");
List<String> lineList =Arrays.asList("1. Hello", "2. I am Fine", "3. What about U ?");
Files.write(filePath, lineList, Charset.forName("UTF-8"));
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但是在文本文件中又生成了一个(第 4 个)空行。如何避免第 4 个空行?
1 | 1. Hello
2 | 2. I am Fine
3 | 3. What about U ?
4 |
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来自 javadoc for write:“每行都是一个字符序列,并按顺序写入文件,每行以平台的行分隔符终止,如系统属性 line.separator 所定义。”
最简单的方法,如你所愿:
List<String> lineList =Arrays.asList("1. Hello", "2. I am Fine");
String lastLine = "3. What about U ?";
Files.write(filePath, lineList, Charset.forName("UTF-8"));
Files.write(filePath, lastLine.getBytes("UTF-8"), StandardOpenOption.APPEND);
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检查Files.write您调用的代码:
public static Path write(Path path, Iterable<? extends CharSequence> lines,
Charset cs, OpenOption... options)
throws IOException
{
// ensure lines is not null before opening file
Objects.requireNonNull(lines);
CharsetEncoder encoder = cs.newEncoder();
OutputStream out = newOutputStream(path, options);
try (BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(out, encoder))) {
for (CharSequence line: lines) {
writer.append(line);
writer.newLine();
}
}
return path;
}
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它在每个插入的末尾创建新行:
writer.newLine();
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解决方案是:提供数据为byte[]:
Path filePath = Paths.get("/Users/maxim/Appsflyer/projects/DEMOS/myFile.txt");
List<String> lineList =Arrays.asList("1. Hello", "2. I am Fine", "3. What about U ?");
String lineListStr = String.join("\n", lineList);
Files.write(filePath, lineListStr.getBytes(Charset.forName("UTF-8")));
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