Lus*_*usi 3 gradle flyway spring-boot
如何在 build.gradle 中配置 Flyway 以从其他属性文件获取 url、用户名、密码?
而不是这个:
flyway {
url = 'jdbc:postgresql://localhost:5432/db'
user = 'a'
password = 'a'
locations = ['filesystem:db/migration']
}
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像这样的东西:
flyway {
path = ['filesystem:src/main/resources/data-access.properties']
locations = ['filesystem:db/migration']
}
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你可以这样做:
ext.flywayProps = new Properties()
flywayProps.load(new FileInputStream(this.projectDir.absolutePath + "/src/main/resources/data-access.properties"))
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在构建脚本的根目录中,它将把属性文件加载到Properties类型的局部变量中。之后,您可以按照需要的方式使用此属性,例如:
flyway {
url = 'jdbc:postgresql://flywayProps['dbIp']:flywayProps['dbPort']/db'
user = flywayProps['dbUsername']
password = flywayProps['dbPassword']
locations = ['filesystem:db/migration']
}
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并且在您中data-access.properties您需要指定它如下:
dbIp=localhost
dbPort=5432
dbUsername=a
dbPassword=a
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