如何要求用户在自定义控制台命令中提供输入？

Question

所以我用两个参数发出命令：

class ServerCommand extends ContainerAwareCommand
{
    protected function configure()
    {
        $this
            ->setName('chat:server')
            ->setDescription('Start the Chat server')
            ->addArgument('host', InputArgument::REQUIRED, 'Provide a hostname')
            ->addArgument('port', InputArgument::OPTIONAL, 'Provide a port number')
        ;
    }

但server:chat命令不要求我提供论据。

如何要求用户在自定义控制台命令中提供输入？

Answer 1

http://symfony.com/doc/current/components/console/helpers/questionhelper.html

protected function configure()
{
    $this
        ->setName('chat:server')
        ->setDescription('Start the Chat server')
        ->addArgument('host', InputArgument::REQUIRED, 'Provide a hostname')
        ->addArgument('port', InputArgument::OPTIONAL, 'Provide a port number')
    ;
}

protected function execute(InputInterface $input, OutputInterface $output)
{
    $helper = $this->getHelper('question');
    $question1 = new Question('Provide a hostname: ', 'localhost');
    $question2 = new Question('Provide a port number: ', '8080');

    $localhost = $helper->ask($input, $output, $question1);
    $port = $helper->ask($input, $output, $question2);

Answer 2

除了 user6827096 的答案之外：还有一种interact()方法可用于使用问题助手从交互式输入中预先填充所需的选项，并且除非--no-interaction传递给命令，否则将被调用：

/**
 * Interacts with the user.
 *
 * This method is executed before the InputDefinition is validated.
 * This means that this is the only place where the command can
 * interactively ask for values of missing required arguments.
 *
 * @param InputInterface  $input  An InputInterface instance
 * @param OutputInterface $output An OutputInterface instance
 */
protected function interact(InputInterface $input, OutputInterface $output)
{
}

与问题助手结合使用的一个很好的例子可以在 Symfony 附带的 Sensio 的 Generator Bundle 中找到：https://github.com/sensiolabs/SensioGeneratorBundle/blob/master/Command/GenerateBundleCommand.php#L112