com*_*mas 6 sql sql-server group-by
我在MSSQL2005中有下表
id | business_key | result
1 | 1 | 0
2 | 1 | 1
3 | 2 | 1
4 | 3 | 1
5 | 4 | 1
6 | 4 | 0
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现在我想根据business_key进行分组,返回id最高的完整条目.所以我的预期结果是:
business_key | result
1 | 1
2 | 1
3 | 1
4 | 0
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我打赌有一种方法可以实现这一点,我现在看不到它.
Tom*_*m H 13
另一种解决方案,可以为您提供更好的性能(测试两种方式并检查执行计划):
SELECT
T1.id,
T1.business_key,
T1.result
FROM
dbo.My_Table T1
LEFT OUTER JOIN dbo.My_Table T2 ON
T2.business_key = T1.business_key AND
T2.id > T1.id
WHERE
T2.id IS NULL
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此查询假定ID是唯一值(至少对于任何给定的business_key)并且它设置为NOT NULL.
select
drv.business_key,
mytable.result
from mytable
inner join
(
select
business_key,
max(id) as max_id
from mytable
group by
business_key
) as drv on
mytable.id = drv.max_id
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