SQL查询:
select type,count(*), 'Active'
from file where removed = '0'
union all
select type,count(*), 'Removed'
from file where removed = '1'
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得到:
TYPE COUNT ( * ) Constant value
A 24,168 Active
A 1 Removed
B 8,280 Active
B 1,263 Removed
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但是,如何更改SQL以获取:
TYPE Active Removed
A 24,168 1
B 8,280 1,263
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补充的可选问题:包含以下总数的最佳方法是什么?
TYPE Active Removed
A 24,168 1
B 8,280 1,263
Total 32,448 1,264
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这是对补充内容的最佳答案,如果您发现任何缺陷或改进,请告诉我:
select
type,
sum(CASE WHEN removed = '0' THEN 1 ELSE 0 END) 'Active',
sum(CASE WHEN removed = '1' THEN 1 ELSE 0 END) 'Removed'
from file
Group by type
union all
select 'Total',
sum(CASE WHEN removed = '0' THEN 1 ELSE 0 END) 'Active',
sum(CASE WHEN removed = '1' THEN 1 ELSE 0 END) 'Removed'
from file
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感谢所有评论或回答的人,感谢您的帮助.
你可以试试:
select
type,
sum(CASE WHEN removed = '0' THEN 1 ELSE 0 END) 'Active',
sum(CASE WHEN removed = '1' THEN 1 ELSE 0 END) 'Removed'
from file
Group by type
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