Alamofire 中的基本身份验证标头

Question

我有一个受保护的 api，我得到了它的用户名和密码。当我使用 Postman 时，我选择了“Basic Auth”类型，在正文中我有用户登录信息等参数。它工作得很好。

但是，我正在尝试使用 Alamofire 做同样的事情，但我无法获得正确的 JSON 返回值。这是我所做的：

  // user auth 
  let param = ["mobile":"3", "password":"100200"]
    let urlStr = "http://MyApi.com/api/login"
    let url = URL(string: urlStr)

    // api auth 
    let user = "apiUserName"
    let password = "ApiAuthPassword"


    var headers: HTTPHeaders = ["mobile":"001",
                                "password":"1111"]

    if let authorizationHeader = Request.authorizationHeader(user: user, password: password) {
        headers[authorizationHeader.key] = authorizationHeader.value
    }

    Alamofire.request(url!, headers: headers)
        .responseJSON { response in

            print(response.result.value)
            if let value: AnyObject = response.result.value as AnyObject? {
                //Handle the results as JSON
                print(value)
                let usertoken = JSON(value)

                print(usertoken)
            }



    }

这将返回零。有人可以帮助我如何使用 Alamofire 执行 Postman 方法。谢谢！

Answer 1

let user = "your username"

let password = "your password"

let credentialData = "\(user):\(password)".data(using: String.Encoding(rawValue: String.Encoding.utf8.rawValue))!

let base64Credentials = credentialData.base64EncodedString()


   let headers = [
            "Authorization": "Basic \(base64Credentials)", 
            "Accept": "application/json",
            "Content-Type": "application/json" ]

//put slash before \ (base64Credentials)

    Alamofire.request("place your url", method: .get, parameters: nil,encoding: URLEncoding.default, headers: headers) .responseJSON { response in
        switch response.result {
            case .success(_):   
               //your success code
            }      
            case .failure(_):
               //your failure code
            }
    }