Ore*_*lus 5 python python-asyncio
我正在尝试两种方法来阻止无限循环运行:
虽然supervisor_2不会引发中断时,在任何错误,我不能让supervisor_1从得到Task was destroyed but it is pending!。知道为什么吗?
这是代码:
import asyncio
import aioredis
from functools import partial
class Listener:
def __init__(self, redis_conn):
self.redis_conn = redis_conn
async def forever(self, loop_name):
counter = 0
try:
while True:
print('{}: {}'.format(loop_name, counter))
counter += 1
await asyncio.sleep(1)
except asyncio.CancelledError:
print('Task Cancelled')
self.redis_conn.close()
await self.redis_conn.wait_closed()
async def supervisor_1(redis_conn):
redis_conn = await redis_conn
l = Listener(redis_conn)
task = asyncio.ensure_future(
asyncio.gather(l.forever('loop_1'),
l.forever('loop_2')))
await asyncio.sleep(2)
task.cancel()
async def supervisor_2(redis_conn):
redis_conn = await redis_conn
l = Listener(redis_conn)
await asyncio.gather(l.forever('loop_1'),
l.forever('loop_2'))
if __name__ == '__main__':
redis_conn = aioredis.create_pool(('localhost', 5003), db=1)
loop = asyncio.get_event_loop()
run = partial(supervisor_2, redis_conn=redis_conn)
task = asyncio.ensure_future(run())
try:
loop.run_until_complete(task)
except KeyboardInterrupt:
print('Interruped !')
task.cancel()
loop.run_forever()
finally:
loop.close()
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@更新:
感谢@Gerasimov,这是一个解决问题的版本,但不知何故仍然不时地在 KeyboardInterrupt 上引发错误:
async def supervisor(redis_conn):
redis_conn = await redis_conn
l = Listener(redis_conn)
task = asyncio.ensure_future(
asyncio.gather(l.forever('loop_1'),
l.forever('loop_2'))
)
await asyncio.sleep(10)
task.cancel()
with suppress(asyncio.CancelledError):
await task
async def kill_tasks():
pending = asyncio.Task.all_tasks()
for task in pending:
task.cancel()
with suppress(asyncio.CancelledError):
await task
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和
if __name__ == '__main__':
redis_conn = aioredis.create_pool(('localhost', 5003), db=1)
loop = asyncio.get_event_loop()
run = partial(supervisor, redis_conn=redis_conn)
task = asyncio.ensure_future(run())
try:
loop.run_until_complete(task)
except KeyboardInterrupt:
print('Interruped !')
loop.run_until_complete(kill_tasks())
finally:
loop.close()
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task.cancel()本身并没有完成任务:它只是对CancelledError应该在其中提出的任务说并立即返回。您应该调用它并等待任务实际上会被取消(而它会引发CancelledError)。
你也不应该压制CancelledError内部任务。
阅读这个答案,我试图展示处理任务的不同方式。例如取消某些任务并等待它取消,您可以执行以下操作:
from contextlib import suppress
task = ... # remember, task doesn't suppress CancelledError itself
task.cancel() # returns immediately, we should await task raised CancelledError.
with suppress(asyncio.CancelledError):
await task # or loop.run_until_complete(task) if it happens after event loop stopped
# Now when we awaited for CancelledError and handled it,
# task is finally over and we can close event loop without warning.
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