Fab*_*pet 10 symfony monolog symfony-3.2
根据此文档,我可以创建许多通道,这些通道将使用以下名称创建服务monolog.logger.<channel_name>
如何通过DI注入和自动装配将这些服务注入我的服务?
class FooService
{
public function __construct(LoggerInterface $loggerInterface) { }
}
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YAML
#existing
foo_service:
class: AppBundle\Services\FooService
arguments: ["@monolog.logger.barchannel"]
# what I want to do
foo_service:
autowire: true # how to inject @monolog.logger.barchannel ?
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我写了(也许更复杂)的方法.我不想标记我的自动服务,以告诉symfony使用哪个频道. 使用symfony 4与php 7.1.
我使用monolog.channels中定义的所有其他通道构建了LoggerFactory.
我的工厂是捆绑的,所以在Bundle.php中添加
$container->addCompilerPass(
new LoggerFactoryPass(),
PassConfig::TYPE_BEFORE_OPTIMIZATION,
1
); // -1 call before monolog
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在monolog.bundle之前调用此编译器是很重要的,因为传递后的monolog会从容器中删除参数.
现在,LoggerFactoryPass
namespace Bundle\DependencyInjection\Compiler;
use Bundle\Service\LoggerFactory;
use Symfony\Component\DependencyInjection\Compiler\CompilerPassInterface;
use Symfony\Component\DependencyInjection\ContainerBuilder;
use Symfony\Component\DependencyInjection\Reference;
class LoggerFactoryPass implements CompilerPassInterface
{
/**
* You can modify the container here before it is dumped to PHP code.
* @param ContainerBuilder $container
* @throws \Symfony\Component\DependencyInjection\Exception\InvalidArgumentException
* @throws \Symfony\Component\DependencyInjection\Exception\ServiceNotFoundException
*/
public function process(ContainerBuilder $container): void
{
if (!$container->has(LoggerFactory::class) || !$container->hasDefinition('monolog.logger')) {
return;
}
$definition = $container->findDefinition(LoggerFactory::class);
foreach ($container->getParameter('monolog.additional_channels') as $channel) {
$loggerId = sprintf('monolog.logger.%s', $channel);
$definition->addMethodCall('addChannel', [
$channel,
new Reference($loggerId)
]);
}
}
}
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和LoggerFactory
namespace Bundle\Service;
use Psr\Log\LoggerInterface;
class LoggerFactory
{
protected $channels = [];
public function addChannel($name, $loggerObject): void
{
$this->channels[$name] = $loggerObject;
}
/**
* @param string $channel
* @return LoggerInterface
* @throws \InvalidArgumentException
*/
public function getLogger(string $channel): LoggerInterface
{
if (!array_key_exists($channel, $this->channels)) {
throw new \InvalidArgumentException('You are trying to reach not defined logger channel');
}
return $this->channels[$channel];
}
}
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所以,现在你可以注入LoggerFactory,并选择你的频道
public function acmeAction(LoggerFactory $factory)
{
$logger = $factory->getLogger('my_channel');
$logger->log('this is awesome!');
}
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您可以使用绑定参数:
services:
_defaults:
autowire: true # Automatically injects dependencies in your services.
autoconfigure: true # Automatically registers your services as commands, event subscribers, etc.
public: true
bind:
$loggerMyApi: '@monolog.logger.my_api'
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然后你可以在你的服务的构造函数中使用它:
use Psr\Log\LoggerInterface;
...
public function __construct(LoggerInterface $loggerMyApi)
{
...
}
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经过一些搜索后,我发现了一些使用标签的解决方法,并手动将几个参数注入自动服务.
我的回答与@ Thomas-Landauer类似.不同的是,我不必手动创建记录器服务,因为编译器从monolog bundle传递给我做了这个.
services:
_defaults:
autowire: true
autoconfigure: true
AppBundle\Services\FooService:
arguments:
$loggerInterface: '@logger'
tags:
- { name: monolog.logger, channel: barchannel }
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从MonologBundle 3.5开始,你可以通过自动装配不同的独白渠道类型暗示的语法如下服务参数:
Psr\Log\LoggerInterface $<channel>Logger
。例如,要注入与应用程序记录器通道相关的服务,请使用:Run Code Online (Sandbox Code Playgroud)public function __construct(LoggerInterface $appLogger) { $this->logger = $appLogger; }
https://symfony.com/doc/current/logging/channels_handlers.html#monolog-autowire-channels
我没有找到自动连接记录器通道的方法。但是,我找到了一种autowire
原则上使用的方法,并且只手动注入记录器。使用您的class FooService
,这就是services.yml
(Symfony 3.3)的样子:
# services.yml
services:
_defaults:
autowire: true
autoconfigure: true
AppBundle\Services\FooService:
arguments:
$loggerInterface: '@monolog.logger.barchannel'
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所以“技巧”是显式注入记录器通道,同时仍然通过自动装配注入该服务的所有其他依赖项。
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