fps - 如何通过时间函数划分计数来确定fps

Question

我有一个计数器工作,计算每一帧.我想要做的是将时间除以确定我的程序的FPS.但我不确定如何在python中对定时函数执行操作.

我已经尝试将时间初始化为

fps_time = time.time 
fps_time = float(time.time)
fps_time = np.float(time.time)
fps_time = time()

然后计算fps,

FPS = (counter / fps_time)
FPS = float(counter / fps_time)
FPS = float(counter (fps_time))

但是我得到的错误是对象是不可调用的或不支持的操作数/:'int'和'buildin functions'

在此先感谢您的帮助!

Answer 1

• 这是一种在每帧打印程序帧速率的简单方法(无需计数器):

  import time
  
  while True:
      start_time = time.time() # start time of the loop
  
      ########################
      # your fancy code here #
      ########################
  
      print("FPS: ", 1.0 / (time.time() - start_time)) # FPS = 1 / time to process loop
  

• 如果你想要平均帧速率超过x秒,你可以这样做(需要计数器):

  import time
  
  start_time = time.time()
  x = 1 # displays the frame rate every 1 second
  counter = 0
  while True:
  
      ########################
      # your fancy code here #
      ########################
  
      counter+=1
      if (time.time() - start_time) > x :
          print("FPS: ", counter / (time.time() - start_time))
          counter = 0
          start_time = time.time()
  

希望能帮助到你!

Answer 2

奇迹般有效

import time
import collections

class FPS:
    def __init__(self,avarageof=50):
        self.frametimestamps = collections.deque(maxlen=avarageof)
    def __call__(self):
        self.frametimestamps.append(time.time())
        if(len(self.frametimestamps) > 1):
            return len(self.frametimestamps)/(self.frametimestamps[-1]-self.frametimestamps[0])
        else:
            return 0.0
fps = FPS()
for i in range(100):
    time.sleep(0.1)
    print(fps())

确保每帧调用一次 fps