从EJB拦截器抛出异常

Question

假设我有一个看起来像这样的拦截器:

public class AuthorizationInterceptor {

  Logger log = Logger.getLogger(getClass().getName());

  @AroundInvoke
  private Object authorize(InvocationContext ic) throws Exception{
    // ... some other logic for authorization

    if (!allowedMethods.contains(ic.getMethod().getName())){
      log.info("Authorization failed. Preparing to throw exception");
      throw new AuthException("Authorization failed for method " +
                ic.getMethod().getName());
    }

    return ic.proceed();
  }
}

这适用于我的EJB的不同方法.

我通常希望将异常throed传递给调用客户端,就像所有正常的EJB异常一样.

显然,如果我从Interceptor中抛出它,就不会发生这种情况......它甚至没有记录在服务器上; 喜欢它永远不会抛出,但它是 - 从不执行return语句.

我究竟做错了什么？

我正在使用GF 3.0.1

Answer 1

这里有一些可以尝试的事情：

1. Check that the authorize(...) method is called.
2. Try making the authorize(...) method public instead of private.
3. Check that the EJB has an annotation like this:
      @Interceptors(AuthorizationInterceptor.class)