ima*_*oob 41 python regex nltk pandas
我已阅读有关此错误的多篇帖子,但我仍然无法弄明白.当我尝试循环我的函数时:
def fix_Plan(location):
letters_only = re.sub("[^a-zA-Z]", # Search for all non-letters
" ", # Replace all non-letters with spaces
location) # Column and row to search
words = letters_only.lower().split()
stops = set(stopwords.words("english"))
meaningful_words = [w for w in words if not w in stops]
return (" ".join(meaningful_words))
col_Plan = fix_Plan(train["Plan"][0])
num_responses = train["Plan"].size
clean_Plan_responses = []
for i in range(0,num_responses):
clean_Plan_responses.append(fix_Plan(train["Plan"][i]))
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这是错误:
Traceback (most recent call last):
File "C:/Users/xxxxx/PycharmProjects/tronc/tronc2.py", line 48, in <module>
clean_Plan_responses.append(fix_Plan(train["Plan"][i]))
File "C:/Users/xxxxx/PycharmProjects/tronc/tronc2.py", line 22, in fix_Plan
location) # Column and row to search
File "C:\Users\xxxxx\AppData\Local\Programs\Python\Python36\lib\re.py", line 191, in sub
return _compile(pattern, flags).sub(repl, string, count)
TypeError: expected string or bytes-like object
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abc*_*ccd 55
正如你在评论中所说,一些值似乎是浮点数,而不是字符串.在传递给字符串之前,您需要将其更改为字符串re.sub.最简单的方法是在使用时更改location为.即使它已经是一个也不会有任何影响.str(location)re.substr
letters_only = re.sub("[^a-zA-Z]", # Search for all non-letters
" ", # Replace all non-letters with spaces
str(location))
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小智 14
最简单的解决方案是应用Python str函数应用于您要循环遍历的列。
如果您正在使用pandas,这可以实现为:
dataframe['column_name']=dataframe['column_name'].apply(str)
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