Dar*_*rov 48
要读取最后1024个字节:
using (var reader = new StreamReader("foo.txt"))
{
if (reader.BaseStream.Length > 1024)
{
reader.BaseStream.Seek(-1024, SeekOrigin.End);
}
string line;
while ((line = reader.ReadLine()) != null)
{
Console.WriteLine(line);
}
}
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也许这样的事情对你有用:
using (var fs = File.OpenRead(filePath))
{
fs.Seek(0, SeekOrigin.End);
int newLines = 0;
while (newLines < 3)
{
fs.Seek(-1, SeekOrigin.Current);
newLines += fs.ReadByte() == 13 ? 1 : 0; // look for \r
fs.Seek(-1, SeekOrigin.Current);
}
byte[] data = new byte[fs.Length - fs.Position];
fs.Read(data, 0, data.Length);
}
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请注意,这是假设\r\n.
下面的代码使用随机访问在文件末尾附近的偏移量处FileStream播种 a ,丢弃第一个读取行,因为它很可能只是部分读取。StreamReader
FileStream stream = new FileStream(@"c:\temp\build.txt",
FileMode.Open, FileAccess.Read);
stream.Seek(-1024, SeekOrigin.End); // rewind enough for > 1 line
StreamReader reader = new StreamReader(stream);
reader.ReadLine(); // discard partial line
while (!reader.EndOfStream)
{
string nextLine = reader.ReadLine();
Console.WriteLine(nextLine);
}
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