Python 3.x无法将Decimal()序列化为JSON

LLL*_*LLL 9 python serialization json python-3.x

我问这个问题前面,它标记为重复这个,但接受的答案不能正常工作,甚至pylint的显示,有代码中的错误.

我想做的事:

from decimal import Decimal
import json

thang = {
    'Items': [{'contact_id': Decimal('2'), 'street_name': 'Asdasd'}, {'contact_id': Decimal('1'), 'name': 'Lukas', 'customer_id': Decimal('1')}],
     'Count': 2}

print(json.dumps(thang))
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抛出: TypeError: Object of type 'Decimal' is not JSON serializable

所以我尝试了链接的答案:

from decimal import Decimal
import json

thang = {
    'Items': [{'contact_id': Decimal('2'), 'street_name': 'Asdasd'}, {'contact_id': Decimal('1'), 'name': 'Lukas', 'customer_id': Decimal('1')}],
     'Count': 2}


class DecimalEncoder(json.JSONEncoder):
    def _iterencode(self, o, markers=None):
        if isinstance(o, Decimal):
            # wanted a simple yield str(o) in the next line,
            # but that would mean a yield on the line with super(...),
            # which wouldn't work (see my comment below), so...
            return (str(o) for o in [o])
        return super(DecimalEncoder, self)._iterencode(o, markers)


print(json.dumps(thang, cls=DecimalEncoder))
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在这里,linter显示该行return super(DecimalEncoder, self)._iterencode(o, markers)有错误,因为Super of 'DecimalEncoder' has no '_iterencode' member并且在运行时抛出 TypeError: Object of type 'Decimal' is not JSON serializable

我该如何工作?

LLL*_*LLL 7

那个答案原来已经过时了,有效的解决方案还有另一个答案

class DecimalEncoder(json.JSONEncoder):
    def default(self, o):
        if isinstance(o, decimal.Decimal):
            return float(o)
        return super(DecimalEncoder, self).default(o)
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  • 这完全违背了Decimal.Decimal类的目的。它应该序列化为字符串而不是浮点数,因为浮点数不准确。 (9认同)
  • 完全同意。将 Decimal 序列化为浮点数的答案不应该是最佳答案,因为它非常不准确。例如,您最终可能会因为浮点舍入错误而违反法律合同。 (2认同)

war*_*ens 6

我想将Decimal序列化为JSON,并将其反序列化回其他地方字典中的实际 Decimal 类对象。

这是我的示例程序(Python 3.6):

import json
from decimal import Decimal
import decimal

class DecimalEncoder(json.JSONEncoder):
    def default(self, obj):
        if isinstance(obj, decimal.Decimal):
            return {'__Decimal__': str(obj)}
        # Let the base class default method raise the TypeError
        return json.JSONEncoder.default(self, obj)

def as_Decimal(dct):
    if '__Decimal__' in dct:
        return decimal.Decimal(dct['__Decimal__'])
    return dct


sample_dict = {
        "sample1": Decimal("100"), 
        "sample2": [ Decimal("2.0"), Decimal("2.1") ],
        "sample3": Decimal("3.1415"),
        "other": "hello!"
    }
print("1. sample_dict is:\n{0}\n".format(sample_dict))

sample_dict_encoded_as_json_string = json.dumps(sample_dict, cls=DecimalEncoder)
print("2. sample_dict_encoded_as_json_string is:\n{0}\n".format(sample_dict_encoded_as_json_string))

sample_dict_recreated = json.loads(sample_dict_encoded_as_json_string, object_hook=as_Decimal)
print("3. sample_dict_recreated is:\n{0}\n".format(sample_dict_recreated))
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这是输出:

1. sample_dict is:
{'sample1': Decimal('100'), 'sample2': [Decimal('2.0'), Decimal('2.1')], 'sample3': Decimal('3.1415'), 'other': 'hello!'}

2. sample_dict_encoded_as_json_string is:
{"sample1": {"__Decimal__": "100"}, "sample2": [{"__Decimal__": "2.0"}, {"__Decimal__": "2.1"}], "sample3": {"__Decimal__": "3.1415"}, "other": "hello!"}

3. sample_dict_recreated is:
{'sample1': Decimal('100'), 'sample2': [Decimal('2.0'), Decimal('2.1')], 'sample3': Decimal('3.1415'), 'other': 'hello!'}
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希望这可以帮助!