我有以下HQL
String FIND_PRODUCT_CLASS_ID = "SELECT pc.id FROM ProductClass pc"+
" JOIN ProductGroup pg ON pc.id = pg.productClassId" +
" JOIN Product p ON pg.id = p.id" +
" JOIN ProductSub ps ON p.id = ps.productId WHERE ps.id =:childProductSubId";
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当我在Spring Hibernate环境中运行此查询时,我得到以下堆栈跟踪.
Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: Path expected for join! [SELECT pc.id FROM com.xxx.domain.ProductClass pc JOIN ProductGroup pg ON pc.id = pg.productClassId JOIN Product p ON pg.id = p.id JOIN ProductSub ps ON p.id = ps.productId WHERE ps.id =:childProductSubId]
at org.hibernate.hql.internal.ast.QuerySyntaxException.convert(QuerySyntaxException.java:91)
at org.hibernate.hql.internal.ast.ErrorCounter.throwQueryException(ErrorCounter.java:109)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:284)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:206)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:158)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:126)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:88)
at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:167)
at org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:301)
at org.hibernate.internal.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:236)
at org.hibernate.internal.SessionImpl.createQuery(SessionImpl.java:1800)
at org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:328)
... 146 more
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但是,如果我修改了没有join像下面这样的关键字的查询,它就会成功.
String FIND_PRODUCT_CLASS_ID = "SELECT pc.id FROM ProductClass pc, ProductGroup pg, " +
" Product p, ProductSub ps where pc.id = pg.productClassId "+
" and pg.id = p.id and p.id = ps.productId and ps.id =:childProductSubId";
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我知道我已经找到了解决方案,但我不确定为什么它不适join用于HQL中的关键字.请给我这个sombody解释一下吗?这与映射有关吗?在我的例子中,对象在Hibernate层中映射.
我们需要在HQL查询中提供路径.这是"加入的预期路径"即将到来的例外情况.
更改如下所示的查询:请根据使用情况进行编辑
String FIND_PRODUCT_CLASS_ID = "SELECT pc.id FROM ProductClass pc"+
" JOIN pc.ProductGroup pg " +
" JOIN pg.Product p " +
" JOIN p.ProductSub ps WHERE ps.id =:childProductSubId";'
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请参考这个.