kab*_*kab 0 python dataframe pandas
我试图根据需要在同一行中满足的 4 个条件从 Pandas DataFrame 中删除一些行。所以我尝试了以下命令:
my_data.drop(my_data[(my_data.column1 is None) & (my_data.column2 is None) & (my_data.column3 is None) & (my_data.column4 is None)].index, inplace=True)
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它抛出这个错误: 在此处输入图像描述
我也试过:
my_data= my_data.loc[my_data[(my_data.column1 is None) & (my_data.column2 is None) & (my_data.column3 is None) & (my_data.column4 is None), :]
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但没有成功
我能得到一些帮助吗:)
我正在研究 python 3.5
通常,使用以下isnull方法检查列是否为空:
df.drop(df[df['column1'].isnull()
& df['column2'].isnull()
& df['column3'].isnull()
& df['column4'].isnull()].index)
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但是,还有更紧凑和惯用的方法:
df.dropna(subset=['column1', 'column2', 'column3', 'column4'], how='all')
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一个演示:
prng = np.random.RandomState(0)
df = pd.DataFrame(prng.randn(100, 6), columns=['column{}'.format(i) for i in range(1, 7)])
df.head()
Out:
column1 column2 column3 column4 column5 column6
0 1.764052 0.400157 0.978738 2.240893 1.867558 -0.977278
1 0.950088 -0.151357 -0.103219 0.410599 0.144044 1.454274
2 0.761038 0.121675 0.443863 0.333674 1.494079 -0.205158
3 0.313068 -0.854096 -2.552990 0.653619 0.864436 -0.742165
4 2.269755 -1.454366 0.045759 -0.187184 1.532779 1.469359
df = df.mask(prng.binomial(1, 0.5, df.shape).astype('bool'), np.nan)
df.head()
Out:
column1 column2 column3 column4 column5 column6
0 NaN 0.400157 NaN 2.240893 NaN NaN
1 0.950088 -0.151357 -0.103219 0.410599 0.144044 NaN
2 0.761038 0.121675 NaN NaN NaN -0.205158
3 NaN NaN -2.552990 NaN 0.864436 NaN
4 2.269755 -1.454366 0.045759 -0.187184 NaN NaN
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以下仅当第 1、3、5 和 6 列为空时才删除行:
df.dropna(subset=['column1', 'column3', 'column5', 'column6'], how='all').head()
Out:
column1 column2 column3 column4 column5 column6
1 0.950088 -0.151357 -0.103219 0.410599 0.144044 NaN
2 0.761038 0.121675 NaN NaN NaN -0.205158
3 NaN NaN -2.552990 NaN 0.864436 NaN
4 2.269755 -1.454366 0.045759 -0.187184 NaN NaN
5 0.154947 0.378163 -0.887786 -1.980796 -0.347912 NaN
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