可能有一种简单的方法来执行此操作,但是我不确定它是什么。我正在尝试使图例中的文本与其旁边的颜色框匹配。我已经尝试了一段时间,但没有找到使用element_text函数向图例添加多种颜色的方法。我使每个标签都具有相同的颜色没有问题,但是有没有办法使每个图例标签具有不同的颜色?
data<-data.frame(count=c(39,36,19,6), category=c("a","b","c","d"))
data$fraction = data$count / sum(data$count)
data = data[order(data$fraction), ]
data$ymax = cumsum(data$fraction)
data$ymin = c(0, head(data$ymax, n=-1))
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#Create Plot
fill <- c("blue3","cyan3","darkgrey","forestgreen")
library(ggplot2)
p1 = ggplot(data, aes(fill=category, ymax=ymax, ymin=ymin, xmax=4, xmin=3.5)) +
geom_rect(colour="White") +
coord_polar(theta="y") +
scale_fill_manual(values=fill)+
theme_bw()+
geom_label(aes(label=paste(data$fraction*100,"%"),x=4,y=
(ymin+ymax)/2),inherit.aes = F)+
theme(panel.grid=element_blank())+
theme(axis.ticks=element_blank()) +
xlim(c(0, 4)) +
theme(axis.text=element_blank()) +
theme(legend.text=element_text(color=fill,size=12))+
theme(legend.key.size=unit(2,'lines'))+
theme(legend.key=element_rect(size=5))+
labs(title="donut plot")
print(p1)
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通过使用该包,无需编辑 grobs 即可实现此目的ggtext
。将图例文本标签指定为element_markdown
并将它们包装在<span>
使用所需颜色的标签中。
data<-data.frame(count=c(39,36,19,6), category=c("a","b","c","d"))
data$fraction = data$count / sum(data$count)
data = data[order(data$fraction), ]
data$ymax = cumsum(data$fraction)
data$ymin = c(0, head(data$ymax, n=-1))
fill <- c("blue3","cyan3","darkgrey","forestgreen")
library(ggplot2)
library(ggtext)
ggplot(data, aes(fill=category, ymax=ymax, ymin=ymin, xmax=4, xmin=3.5)) +
geom_rect(colour="White") +
coord_polar(theta="y") +
scale_fill_manual(labels = paste("<span style='color:",
fill,
"'>",
unique(data$category),
"</span>"),
values = fill)+
theme_bw()+
geom_label(aes(label=paste(data$fraction*100,"%"),x=4,y=
(ymin+ymax)/2),inherit.aes = F)+
theme(panel.grid=element_blank())+
theme(axis.ticks=element_blank()) +
xlim(c(0, 4)) +
theme(axis.text=element_blank()) +
theme(legend.text=element_markdown(size=12))+
theme(legend.key.size=unit(2,'lines'))+
theme(legend.key=element_rect(size=5))+
labs(title="donut plot")
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编辑:删除图例的一种方法是使用theme(legend.position = "none")
:
ggplot(data, aes(fill=category, ymax=ymax, ymin=ymin, xmax=4, xmin=3.5)) +
geom_rect(colour="White") +
coord_polar(theta="y") +
scale_fill_manual(labels = paste("<span style='color:",
fill,
"'>",
unique(data$category),
"</span>"),
values = fill)+
theme_bw()+
geom_label(aes(label=paste(data$fraction*100,"%"),x=4,y=
(ymin+ymax)/2),inherit.aes = F)+
theme(panel.grid=element_blank()) +
theme(axis.ticks=element_blank()) +
xlim(c(0, 4)) +
theme(axis.text=element_blank()) +
theme(legend.position = "none")+
labs(title="donut plot")
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通过对该答案进行一些修改,将文本文本颜色匹配到符号,您将获得所需的内容。但请注意,答案使用grid
的编辑功能。
# Your data and plot
data<-data.frame(count=c(39,36,19,6), category=c("a","b","c","d"))
data$fraction = data$count / sum(data$count)
data = data[order(data$fraction), ]
data$ymax = cumsum(data$fraction)
data$ymin = c(0, head(data$ymax, n=-1))
fill <- c("blue3","cyan3","darkgrey","forestgreen")
library(ggplot2)
p1 = ggplot(data, aes(fill=category, ymax=ymax, ymin=ymin, xmax=4, xmin=3.5)) +
geom_rect(colour="White") +
coord_polar(theta="y") +
scale_fill_manual(values=fill)+
theme_bw()+
geom_label(aes(label=paste(data$fraction*100,"%"),x=4,y=
(ymin+ymax)/2),inherit.aes = F)+
theme(panel.grid=element_blank())+
theme(axis.ticks=element_blank()) +
xlim(c(0, 4)) +
theme(axis.text=element_blank()) +
theme(legend.text=element_text(color=fill,size=12))+
theme(legend.key.size=unit(2,'lines'))+
theme(legend.key=element_rect(size=5))+
labs(title="donut plot")
# Get the ggplot grob
g <- ggplotGrob(p1)
# Check out the grobs
library(grid)
grid.ls(grid.force(g))
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浏览清单列表。您要编辑的杂项位于列表的底部,即“指南框”中的一组杂项-名称以“标签”开头。有四个技巧:
标签-3-3.4-4-4-4
标签-4-3.5-4-5-4
标签-5-3.6-4-6-4
标签-6-3.7-4-7-4
# Get names of 'label' grobs.
names.grobs <- grid.ls(grid.force(g))$name
labels <- names.grobs[which(grepl("^label", names.grobs))]
# Edit the 'label' grobs - change their colours
# Use the `editGrob` function
for(i in seq_along(labels)) {
g <- editGrob(grid.force(g), gPath(labels[i]), grep = TRUE,
gp = gpar(col = fill[i]))
}
# Draw it
grid.newpage()
grid.draw(g)
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