图中每个因子水平的颜色

Dri*_*ies 4 r plotly

一个客户要我做像一个阴谋这样.此引用使用rgl-package,但导出数字的质量太低.因此,我从剧情开始.我可以管理我想要做的大部分事情,但由于某种原因,所有的酒吧都有不同的颜色.

MWE:

X<-1:60
Y<-sort(runif(60,-3,3))
Z<-runif(60,0,50)

p<-plot_ly(x = c(X[1],X[1]+1,X[1]+1,X[1]),
    y = c(0,0,Y[1],Y[1]), z=c(0,0,0,0),type = "mesh3d",color=I("red"))

for(i in X){p<-add_trace(p,x = c(i,i+1,i+1,i), 
          y = c(0,0,Y[i],Y[i]),  z=c(0,0,0,0),type = "mesh3d",color=I("red"))}
for(i in X){p<-add_trace(p,x = c(i,i+1,i+1,i), 
          y = c(0,0,0,0), z=c(0,0,Z[i],Z[i]),type = "mesh3d",i=c(0,0),
         j=c(1,2),k=c(2,3),color=I("black"))}

p
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虽然我期待红色和黑色的东西,但我得到了这个多彩的结果: 在此输入图像描述

我实际上正在寻找的是类似下面的内容,每个因子级别都有一个颜色,但是现在,结果与上面的相同:

X<-1:60
Y<-sort(runif(60,-3,3)) 
Z<-runif(60,0,50)
ColFactor<-sample(c(0,1),60,replace = TRUE)

p<-plot_ly(x = c(X[1],X[1]+1,X[1]+1,X[1]), y = c(0,0,Y[1],Y[1]), z=c(0,0,0,0),
    type = "mesh3d",color=ColFactor,colors=c("red","blue"))

for(i in X){p<-add_trace(p,x = c(i,i+1,i+1,i), y = c(0,0,Y[i],Y[i]), z=c(0,0,0,0),
    type = "mesh3d",color=ColFactor,colors=c("red","blue"))}
for(i in X){p<-add_trace(p,x = c(i,i+1,i+1,i), y = c(0,0,0,0), z=c(0,0,Z[i],Z[i]),
    type = "mesh3d",i=c(0,0),j=c(1,2),k=c(2,3),color=I("black"))}

p
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小智 7

当你按照你打算的方式使用plot_ly时,似乎存在某种问题.但是,有一种解决方法(https://github.com/ropensci/plotly/issues/413).为了使工作正常,你必须通过plotly_build函数覆盖plot_ly提供的默认值.

以下代码应该可以获得水平和垂直条具有不同颜色的图:

X<-1:60
Y<-sort(runif(60,-3,3))
Z<-runif(60,0,50)
ColFactor<-sample(c(0,1),60,replace = TRUE)

p<-plot_ly(color=I("black")) #This plot a layout where to add the traces and adds
                        #the attribute color needed when overriding  default. If it isn't included it doesn't work
                        #Which color you use here is unimportant, it will be override

#next lines add the bars, if you plot the result will be the same that you already know
for(i in X){p<-add_trace(p,x = c(i,i+1,i+1,i), 
                     y = c(0,0,Y[i],Y[i]),  z=c(0,0,0,0),type = "mesh3d")}
for(i in X){p<-add_trace(p,x = c(i,i+1,i+1,i), 
                     y = c(0,0,0,0), z=c(0,0,Z[i],Z[i]),type = "mesh3d",i=c(0,0),
                     j=c(1,2),k=c(2,3))}

#next step: override the defaults options using plotly_build()

p.optionslist<-plotly_build(p)

#you have to change every trace individually that's what the for loop is

#horizontal bars    
for(j in 1:((length(p.optionslist$x$data))/2)){
    p.optionslist$x$data[[j]]$color=toRGB("red")
}

#horizontal vertical bars
for(j in (((length(p.optionslist$x$data)/2)+1):length(p.optionslist$x$data))){
p.optionslist$x$data[[j]]$color=toRGB("blue")
}

#The plot
p.optionslist
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没有因素

关于ColFactor的使用,以下代码有效(当然有更好的方法,但我不知道哪一个)

#overriding color option according to the value of ColFactor
p.optionslist2<-plotly_build(p)


for(j in 1:((length(p.optionslist2$x$data))/2)){
  if(ColFactor[j]==1){
    p.optionslist2$x$data[[j]]$color=toRGB("red")
  }else{
    p.optionslist2$x$data[[j]]$color=toRGB("blue")
  }
}

for(j in (((length(p.optionslist2$x$data))/2)+1):length(p.optionslist2$x$data)){
  i=j-length(ColFactor)
  if(ColFactor[i]==1){
    p.optionslist2$x$data[[j]]$color=toRGB("red")
  }else{
    p.optionslist2$x$data[[j]]$color=toRGB("blue")
  }
}

#The plot with color by 
p.optionslist2
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在此输入图像描述

如果您希望垂直条全部为黑色,水平条全部为因子,则您只需要组合两个选项:

p.optionslist3<-plotly_build(p)


for(j in 1:((length(p.optionslist3$x$data))/2)){
  if(ColFactor[j]==1){
    p.optionslist3$x$data[[j]]$color=toRGB("red")
  }else{
    p.optionslist3$x$data[[j]]$color=toRGB("blue")
  }
}

for(j in (((length(p.optionslist3$x$data))/2)+1):length(p.optionslist3$x$data)){
  p.optionslist3$x$data[[j]]$color=toRGB("black")
}

#The plot with color by 
p.optionslist3
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在此输入图像描述

希望它能帮到你!