从Jenkins声明性管道设置构建名称和描述

Question

我想从Jenkins Declarative Pipeline设置构建名称和描述,但找不到正确的方法.我尝试在管道之后使用环境支架,在代理程序括号中使用节点括号等.我总是遇到语法错误.

我的Jenkinsfile的最后一个版本是这样的:

pipeline {  
    stages {
        stage("Build") {
            steps {
                echo "Building application..."
                bat "%ANT_HOME%/bin/ant.bat clean compile"
                currentBuild.name = "MY_VERSION_NUMBER"
                currentBuild.description = "MY_PROJECT MY_VERSION_NUMBER"
            }
        }
        stage("Unit Tests") {
            steps {
                echo "Testing (JUnit)..."
            echo "Testing (pitest)..."
                bat "%ANT_HOME%/bin/ant.bat run-unit-tests"
            }
        }
        stage("Functional Test") {
            steps {
                echo "Selenium..."
            }
        }
        stage("Performance Test") {
            steps {
                echo "JMeter.."
            }
        }
        stage("Quality Analysis") {
            steps {
                echo "Running SonarQube..."
                bat "%ANT_HOME%/bin/ant.bat run-sonarqube-analysis"
            }
        }
        stage("Security Assessment") {
            steps {
                echo "ZAP..."
            }
        }
        stage("Approval") {
            steps {
            echo "Approval by a CS03"
            }
        }
        stage("Deploy") {
            steps {
                echo "Deploying..."
            }
        }
    }
    post {      
        always {
            junit '/test/reports/*.xml'
        }
        failure {
            emailext attachLog: true, body: '', compressLog: true, recipientProviders: [[$class: 'CulpritsRecipientProvider'], [$class: 'DevelopersRecipientProvider']], subject: '[JENKINS] MY_PROJECT build failed', to: '...recipients...'
        }
        success {
            emailext attachLog: false, body: '', compressLog: false, recipientProviders: [[$class: 'DevelopersRecipientProvider']], subject: '[JENKINS] MY_PROJECT build succeeded', to: '...recipients...'
        }
    }       
}

错误是:

org.codehaus.groovy.control.MultipleCompilationErrorsException: startup failed:
WorkflowScript: 11: Expected a step @ line 11, column 5.
                currentBuild.name = "MY_VERSION_NUMBER"
       ^

WorkflowScript: 12: Expected a step @ line 12, column 5.
                currentBuild.description = "MY_PROJECT MY_VERSION_NUMBER"
       ^

理想情况下,我希望能够从build.properties文件或Jenkins构建日志中读取MY_PROJECT和MY_VERSION_NUMBER.关于该要求的任何指导也将受到赞赏.

UPDATE

根据我在下面的答案,以下工作:

stage("Build") {
    steps {
        echo "Building application..."
        bat "%ANT_HOME%/bin/ant.bat clean compile"

        script {
            def props = readProperties  file: 'build.properties'
            currentBuild.displayName = "v" + props['application.version']
        }
    }

现在,通过读取build.properties文件,在管道期间自动设置构建版本.

Answer 1

我想这会做你想要的.我能够在一个script街区内完成:

pipeline {
    stages {
        stage("Build"){
            steps {
                script {
                    currentBuild.displayName = "The name."
                    currentBuild.description = "The best description."
                }
                ... do whatever.
            }
        }
    }
}

该脚本是逃离声明性管道的一种逃避方法.可能有一种声明性的方式来做,但我找不到它.还有一点需要注意.我想你想要currentBuild.displayName而不是currentBuild.name 在Jenkins全局文件的文档中,我没有在currentBuild下看到name属性.

Answer 2

如果要通过参数为作业设置内部版本名称，则可以使用

currentBuild.displayName = "${nameOfYourParameter}"。 确保使用双引号而不是单引号。

作业配置

使用参数构建作业

建立历史

参考：如何在管道作业中设置内部版本名称？