C++ std :: get <variable>失败

Question

如何使用变量使用std :: get <>索引到元组？我有以下代码:

#include <iostream>
#include <tuple>
using namespace std;

int main() {
  tuple<int, int> data(5, 10);
  for (int i=0; i<2; i++) {
    cout << "#" << i+1 << ":" << get<i>(data) << endl;
  }
  return 0;
}

它失败并出现以下编译器错误:

prog.cpp: In function 'int main()':
prog.cpp:10:39: error: the value of 'i' is not usable in a constant expression
      cout << "#" << i+1 << ":" << get<i>(data) << endl;
                                       ^
prog.cpp:9:11: note: 'int i' is not const
  for (int i=0; i<2; i++) {
           ^
prog.cpp:10:46: error: no matching function for call to 
    'get(std::tuple<int, int>&)'
          cout << "#" << i+1 << ":" << get<i>(data) << endl;
                                          ^
prog.cpp:10:46: note: candidates are:
In file included from /usr/include/c++/4.9/tuple:38:0,
                 from prog.cpp:2:
/usr/include/c++/4.9/utility:143:5: note: template<unsigned int _Int, 
class _Tp1, class _Tp2> constexpr typename std::tuple_element<_Int, 
std::pair<_Tp1, _Tp2> >::type& std::get(std::pair<_Tp1, _Tp2>&)
     get(std::pair<_Tp1, _Tp2>& __in) noexcept
     ^
/usr/include/c++/4.9/utility:143:5: note:   template argument 
deduction/substitution failed:
prog.cpp:10:46: error: the value of 'i' is not usable in a constant 
expression
      cout << "#" << i+1 << ":" << get<i>(data) << endl;
                                              ^
prog.cpp:9:11: note: 'int i' is not const
  for (int i=0; i<2; i++) {
           ^
prog.cpp:10:46: note: in template argument for type 'unsigned int' 
      cout << "#" << i+1 << ":" << get<i>(data) << endl;
                                              ^
In file included from /usr/include/c++/4.9/tuple:38:0,
                 from prog.cpp:2:
/usr/include/c++/4.9/utility:148:5: note: template<unsigned int _Int, 
class _Tp1, class _Tp2> constexpr typename std::tuple_element<_Int, 
std::pair<_Tp1, _Tp2> >::type&& std::get(std::pair<_Tp1, _Tp2>&&)
     get(std::pair<_Tp1, _Tp2>&& __in) noexcept
     ^
/usr/include/c++/4.9/utility:148:5: note:   template argument 
deduction/substitution failed:
prog.cpp:10:46: error: the value of 'i' is not usable in a constant 
expression
      cout << "#" << i+1 << ":" << get<i>(data) << endl;
                                              ^
prog.cpp:9:11: note: 'int i' is not const
  for (int i=0; i<2; i++) {
           ^
prog.cpp:10:46: note: in template argument for type 'unsigned int' 
      cout << "#" << i+1 << ":" << get<i>(data) << endl;
                                              ^
In file included from /usr/include/c++/4.9/tuple:38:0,
                 from prog.cpp:2:
/usr/include/c++/4.9/utility:153:5: note: template<unsigned int _Int, 
class _Tp1, class _Tp2> constexpr const typename 
std::tuple_element<_Int, std::pair<_Tp1, _Tp2> >::type& std::get(const 
std::pair<_Tp1, _Tp2>&)
     get(const std::pair<_Tp1, _Tp2>& __in) noexcept
     ^
/usr/include/c++/4.9/utility:153:5: note:   template argument 
deduction/substitution failed:
prog.cpp:10:46: error: the value of 'i' is not usable in a constant 
expression
      cout << "#" << i+1 << ":" << get<i>(data) << endl;
                                              ^
prog.cpp:9:11: note: 'int i' is not const
  for (int i=0; i<2; i++) {
           ^
prog.cpp:10:46: note: in template argument for type 'unsigned int' 
      cout << "#" << i+1 << ":" << get<i>(data) << endl;
                                              ^
In file included from /usr/include/c++/4.9/tuple:38:0,
                 from prog.cpp:2:
/usr/include/c++/4.9/utility:162:5: note: template<class _Tp, class 
_Up> constexpr _Tp& std::get(std::pair<_T1, _T2>&)
     get(pair<_Tp, _Up>& __p) noexcept

我实际上截断了编译器错误消息,因为我认为它没有超出这一点.知道如何做到这一点吗？

编辑:

只是为了澄清,使用array 类型并不是一个真正的选择.我必须使用tuple它的原因,它是来自第三方库的API的返回类型.上面的例子只是为了让它易于理解.

Answer 1

如何使用变量使用std :: get <>索引到元组？

你没有,std::get<>参数值必须在编译时知道.

知道如何做到这一点吗？

是的,使用正确的类型:

int main() {
  std::array<int, 2> data{ 5, 10 };
  for (int i=0; i<2; i++) {
    cout << "#" << i+1 << ":" << data[i] << endl;
  }
  return 0;
}

Answer 2

知道如何让它发挥作用吗？

选项1

使用编译时常量访问std::tuple.

cout << "#" << 1 << ":" << get<0>(data) << endl;
cout << "#" << 2 << ":" << get<1>(data) << endl;

选项2

使用可以在运行时使用索引访问其元素的容器类型。

std::vector<int> data{5, 10};

或者

std::array<int, 2> data{5, 10};