Laravel:将参数传递给函数？

Question

我试图将两个参数传递给whereHas与Laravel的函数,因为其他它不能使用$businessid但它抛出错误,任何人都可以帮忙吗？

错误:

HomeController.php第16行中的FatalThrowableError:类型错误:函数App\Http\Controllers\Business\User\HomeController :: App\Http\Controllers\Business\User {closure}()的参数太少,1传递给C:\第938行的web\vendor\laravel\framework\src\Illuminate\Database\Eloquent\Builder.php,预计正好2

码:

<?php

namespace App\Http\Controllers\Business\User;

use App\User;
use App\Http\Controllers\Controller;
use Illuminate\Http\Request;
use Auth;
use App\Database\Frontend\Roleplay\Business\Businesses;
use App\Database\Frontend\User\Player;

class HomeController extends Controller
{
    public function getView(Request $request, $businessid)
    {
        $workerCount = Player::whereHas("roleplay", function($q2, $businessid) {
            $q2->where('business_id', $businessid);
        })->count();

        $workersWorkingCount = Player::where('currently_working', '1')->whereHas("roleplay", function($q2, $businessid) {
            $q2->where('business_id', $businessid);
        })->count();

        $workersOnlineCount = Player::where('online', '1')->whereHas("roleplay", function($q2, $businessid) {
            $q2->where('business_id', $businessid);
        })->count();

        $workersOfflineCount = Player::where('online', '0')->whereHas("roleplay", function($q2, $businessid) {
            $q2->where('business_id', $businessid);
        })->count();

        return view('business.home', compact(
            'workerCount',
            'workersWorkingCount',
            'workersOnlineCount',
            'workersOfflineCount'));
    }
}

Answer 1

这是你可以将变量传递给函数的方法.

        $workerCount = Player::whereHas("roleplay", function($q2) use ($businessid) {
            $q2->where('business_id', $businessid);
        })->count();