Cla*_*ire 10 php forms recaptcha
对于为什么这不起作用感到困惑.提交表单时,我收到错误消息,这意味着我的重新验证失败.
从我的形式:
<div class="g-recaptcha" data-sitekey="(site-key)"></div>
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PHP:
if(isset($_POST['g-recaptcha-response'])){
$captcha=$_POST['g-recaptcha-response'];
}
$secretKey = "(secret-key)";
$response = file_get_contents("https://www.google.com/recaptcha/api/siteverify?secret=".$secretKey."&response=".$captcha);
$responseKeys = json_decode($response,true);
if(intval($responseKeys["success"]) === true) {
echo '<h3>Thanks for your message!</h3>';
} else {
echo '<h3>Error</h3>';
}
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Yem*_*iez 26
reCaptcha文档明确指定必须通过POST发送https://www.google.com/recaptcha/api/siteverify请求的参数.您可以使用CURL.
$ch = curl_init();
curl_setopt_array($ch, [
CURLOPT_URL => 'https://www.google.com/recaptcha/api/siteverify',
CURLOPT_POST => true,
CURLOPT_POSTFIELDS => [
'secret' => $secretKey,
'response' => $captcha,
'remoteip' => $_SERVER['REMOTE_ADDR']
],
CURLOPT_RETURNTRANSFER => true
]);
$output = curl_exec($ch);
curl_close($ch);
$json = json_decode($output);
// check response...
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小智 8
不要用file_get_contents.谷歌建议使用POST请求.您可以使用以下行中的内容
$curl = curl_init();
curl_setopt_array($curl, array(
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_URL => 'https://www.google.com/recaptcha/api/siteverify',
CURLOPT_POST => 1,
CURLOPT_POSTFIELDS => array(
'secret' => $secretKey,
'response' => $captcha
)
));
$response = curl_exec($curl);
curl_close($curl);
if(strpos($response, '"success": true') !== FALSE) {
echo '<h3>Thanks for your message!</h3>';
} else {
echo "<h3>Error</h3>";
}
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编辑
通过使用该json_decode功能,Yemiez回答(刚刚让我在角落里)更好地处理响应部分.
编辑 只是修正了一个错字
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