续集中一张表中同一表的两个外键

Question

我的团队成员模特: -

var teamMember = {
    id: {
        type: DataTypes.INTEGER,
        primaryKey: true,
        autoIncrement: true
    },
    level: DataTypes.INTEGER,
    supervisorId: {
        type: DataTypes.INTEGER,
        references: {
            model: "employees",
            key: "id"
        }
    },
    employeeId: {
        type: DataTypes.INTEGER,
        unique: true,
        references: {
            model: "employees",
            key: "id"
        }
    }

并且有员工模型

制图: -

db.employee.hasOne(db.teamMember);
db.teamMember.belongsTo(db.employee);

我的查询功能

        db.teamMember.findOne({
        where: { employeeId: req.employee.id },
        include: [db.employee]

    })
    .then(teamMember => {
        if (!teamMember) {
            throw ('no teamMember found');
        }
       consol.log(teamMember)
    })

我的teamMember表就像=

ID ------雇员------ supervisorId

2 ----------- 4 ------------- 5

问题是 - :所以当我在teamMember中询问其employeeId为4.应该包含在supervisorId(JOIN)中的行时,它返回包含4(id)的员工的行.我想要第5个身份的员工.

supervisorId和employeeId都是employee表的reffer.

Answer 1

您不需要在模型上设置员工和主管的字段,只需执行所有它将添加它,并且您可以在那里指定if是唯一的并使用"as",这样您就可以了解员工是否正在引用加入,正式员工或主管,如下所示:

db.teamMember.belongsTo(db.employee, {as: 'SupervisorId'});
db.teamMember.belongsTo(db.employee, {as: 'RegularEmployeeId'});

然后在您的查询中添加如下所示的包含:

include: [{
    model: db.employee,
    as: 'SupervisorId
}]