检测当前视图外的任何水龙头

Question

有没有办法检测当前视图外的任何水龙头？我试图用hitTest方法实现某些功能但未成功,但我不确定是否理解它.

Answer 1

您需要做的是,在touchesBegan中,您必须从触摸设置中获取第一个触摸对象,并且您必须在视图中检查该触摸的位置(您要在其中检测触摸).

当您在搜索得到触摸的位置,你必须检查你是否currentView(你必须检查水龙头是否是内部或外部的观点).

如果currentView的框架包含触摸位置,则表示在视图内部发生了触摸,否则在外部.

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
        let touch = touches.first
        guard let location = touch?.location(in: self.view) else { return }
        if !currentView.frame.contains(location) {
            print("Tapped outside the view")
        }else {
            print("Tapped inside the view")
        }
    }

希望能帮助到你!

Answer 2

您可以使用UIGestureRecognizerDelegate协议

    extension YourViewController: UIGestureRecognizerDelegate {

      func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer,
                             shouldReceive touch: UITouch) -> Bool {
        return (touch.view === self.view)
      } 
    }

当触摸在背景视图上时,此选项仅返回"true",如果在视图内部,则返回"false".

注意:身份运算符===将touch.view与self.view进行比较.您想知道两个变量是否都引用同一个对象.

在viewDidLoad()中,您将创建gestureRecognizer并设置委托.

let gestureRecognizer = UITapGestureRecognizer(target: self,action: #selector(yourActionMethod))
gestureRecognizer.cancelsTouchesInView = false
gestureRecognizer.delegate = self
view.addGestureRecognizer(gestureRecognizer)