如果值相同,Python Pandas将列从df复制到另一个

Question

我有两个数据帧:

DF ONE:

ID     A    B    C
 1     x    y    z
 1     x    y    z
 2     x    y    z
 2     x    y    z
 2     x    y    z
 3     x    y    z

DF TWO:

ID     D    E    F
 1     a    b    c1
 2     a    b    c2
 3     a    b    c3

我想E从DF TWO中获取列,并将其放在DF ONE上,如果ID相同,那么在我得到此输出之后:

ID     A    B    C    F
 1     x    y    z    c1
 1     x    y    z    c1
 2     x    y    z    c2
 2     x    y    z    c2
 2     x    y    z    c2
 3     x    y    z    c3

谢谢您的帮助

Answer 1

您可以使用map通过dict:

d = df2.set_index('ID')['F'].to_dict()
print (d)
{1: 'c1', 2: 'c2', 3: 'c3'}

df1['F'] = df1['ID'].map(d)
print (df1)
   ID  A  B  C   F
0   1  x  y  z  c1
1   1  x  y  z  c1
2   2  x  y  z  c2
3   2  x  y  z  c2
4   2  x  y  z  c2
5   3  x  y  z  c3

另一种解决方案是map通过Series:

s = df2.set_index('ID')['F']
print (s)
ID
1    c1
2    c2
3    c3
Name: F, dtype: object

df1['F'] = df1['ID'].map(s)
print (df1)
   ID  A  B  C   F
0   1  x  y  z  c1
1   1  x  y  z  c1
2   2  x  y  z  c2
3   2  x  y  z  c2
4   2  x  y  z  c2
5   3  x  y  z  c3

时间:

#[60000 rows x 5 columns]
df1 = pd.concat([df1]*10000).reset_index(drop=True)

In [115]: %timeit pd.merge(df1, df2[['ID', 'F']],how='left')
100 loops, best of 3: 11.1 ms per loop

In [116]: %timeit df1['ID'].map(df2.set_index('ID')['F'])
100 loops, best of 3: 3.18 ms per loop

In [117]: %timeit df1['ID'].map(df2.set_index('ID')['F'].to_dict())
100 loops, best of 3: 3.36 ms per loop

In [118]: %timeit df1['ID'].map({k:v for k, v in df2[['ID', 'F']].as_matrix()})
100 loops, best of 3: 3.44 ms per loop

In [119]: %%timeit 
     ...: df2.index = df2['ID']
     ...: df1['F1'] = df1['ID'].map(df2['F'])
     ...: 
100 loops, best of 3: 3.33 ms per loop