groupby.apply(..)后Pandas drop group列

Question

        uid  iid  val
uid                 
1   1    1    5   5.5
2   3    1    4   3.5
2   2    1    4   3.5
2   7    1    4   3.5
2   9    1    4   3.5
2   11   1    4   3.5

从上面的数据框中,我想删除第一列,即:

uid
1
2
2
2
2
2

并提取

    uid  iid  val

1    1    5   5.5
3    1    4   3.5
2    1    4   3.5
7    1    4   3.5
9    1    4   3.5
11   1    4   3.5

有人可以帮忙吗？

Answer 1

您可以uid通过传递group_keys=False到第一位来避免在索引中包含groupby

df.groupby('uid', group_keys=False).apply(lambda x: x.tail(len(x) // 5))

   uid  iid  val
4    1    5  5.5

Answer 2

使用reset_index或droplevel:

df = df.reset_index(level=0, drop=True)


df = df.reset_index(level='uid', drop=True)

要么:

df.index = df.index.droplevel(0)