Arn*_*old 4 python logarithm axes matplotlib
我正在尝试使用 math.log(1+x) 而不是通常的“log”比例选项来缩放绘图的 x 轴,并且我查看了一些自定义缩放示例,但我无法得到我的上班!这是我的 MWE:
import matplotlib.pyplot as plt
import numpy as np
import math
from matplotlib.ticker import FormatStrFormatter
from matplotlib import scale as mscale
from matplotlib import transforms as mtransforms
class CustomScale(mscale.ScaleBase):
name = 'custom'
def __init__(self, axis, **kwargs):
mscale.ScaleBase.__init__(self)
self.thresh = None #thresh
def get_transform(self):
return self.CustomTransform(self.thresh)
def set_default_locators_and_formatters(self, axis):
pass
class CustomTransform(mtransforms.Transform):
input_dims = 1
output_dims = 1
is_separable = True
def __init__(self, thresh):
mtransforms.Transform.__init__(self)
self.thresh = thresh
def transform_non_affine(self, a):
return math.log(1+a)
def inverted(self):
return CustomScale.InvertedCustomTransform(self.thresh)
class InvertedCustomTransform(mtransforms.Transform):
input_dims = 1
output_dims = 1
is_separable = True
def __init__(self, thresh):
mtransforms.Transform.__init__(self)
self.thresh = thresh
def transform_non_affine(self, a):
return math.log(1+a)
def inverted(self):
return CustomScale.CustomTransform(self.thresh)
# Now that the Scale class has been defined, it must be registered so
# that ``matplotlib`` can find it.
mscale.register_scale(CustomScale)
z = [0,0.1,0.3,0.9,1,2,5]
thick = [20,40,20,60,37,32,21]
fig = plt.figure(figsize=(8,5))
ax1 = fig.add_subplot(111)
ax1.plot(z, thick, marker='o', linewidth=2, c='k')
plt.xlabel(r'$\rm{redshift}$', size=16)
plt.ylabel(r'$\rm{thickness\ (kpc)}$', size=16)
plt.gca().set_xscale('custom')
plt.show()
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量表由两个 Transform 类组成,每个类都需要提供一个transform_non_affine方法。一个类需要从数据转换为显示坐标,这将是log(a+1),另一个类是相反的,需要从显示坐标转换为数据坐标,在本例中为exp(a)-1。
这些方法需要处理 numpy 数组,因此它们应该使用各自的 numpy 函数而不是 math 包中的函数。
class CustomTransform(mtransforms.Transform):
....
def transform_non_affine(self, a):
return np.log(1+a)
class InvertedCustomTransform(mtransforms.Transform):
....
def transform_non_affine(self, a):
return np.exp(a)-1
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